Part a)
for extraneous solution
<span>
1 ⋅ sqrt(x+2) + 3 = 0</span>
for non extraneous solution
1⋅ sqrt(x+2) + 3 = 6
part b) solve each equation
1⋅sqrt(x+2)+3=0
x+sqrt(x+2)=−3
square both sides
(sqrt(<span>x+2)</span>)^ 2 = (−3)^2
x+2=9
x=9−2
x=7
do you see why its extraneous
Answer:
223.2725
Step-by-step explanation:
223.2725
Answer:
14, 48, 50
Step-by-step explanation:
To check which set of side length can be used to form a right triangle we use pythagorean theorem
c^2 = a^2 + b^2
biggest side (hypotenuse is c^2)
(a) 14, 48, 50

2500= 196+2304
2500= 2500 that is true
(b) 30, 40, 60

3600= 900+ 1600
3600= 2500 that is false
(c) 14, 50, 60

3600= 196+2500
2500= 2196 that is false
(d) 10, 24,28

784=100+576
784=676 that is false
Answer: it is stretched vertically by a factor of 3
Step-by-step explanation:i make a unit test and get 100% that is correct.
I hope This help;)