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oksano4ka [1.4K]
3 years ago
15

A plumber charges $15 for a service call plus $20 per hour of service. Write an equation in slope-intercept form for the cost, y

, after x hours of service. What will be the total cost for 8 hours of work?
Select the correct equation and solution (you should pick two answers.)

Y=15x + 20
Y= 20x + 15
140 dollars
175 dollars
Mathematics
1 answer:
artcher [175]3 years ago
6 0

Answer:

Y=20x+15 & 175 dollars

Step-by-step explanation:

The word problems says $20 per hour, so that means 20 times the amount of hours. If yo multiply 20 times 8 you get 160. Add 15 to 160, you end up with $175.

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Values greater then 1653
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1654,1655,1656,1657,1658,1659,1660

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They all come after the value of 1653

7 0
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9.25x - 1201≥ 185 please help​
iVinArrow [24]

Answer:

x≥149.84

Step-by-step explanation:

solve for x the inequality

9.25x - 1201 ≥ 185

9.25x ≥ 185+1201

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4 0
3 years ago
WILL MARK BRAINLIEST!
Maurinko [17]

Answer:

  A)  square; rectangle; rhombus

Step-by-step explanation:

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7 0
3 years ago
Teen obesity:
Law Incorporation [45]

Answer:

95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

Step-by-step explanation:

We are given that 15% of a random sample of 300 U.S. public high school students were obese.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

                        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample % of U.S. public high school students who were obese = 15%

           n = sample of U.S. public high school students = 300

           p = population percentage of all U.S. public high school students

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

<u></u>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

  = [ 0.15-1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } } , 0.15+1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } } ]

  = [0.110 , 0.190]

Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

6 0
3 years ago
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