Step-by-step explanation:
3(p2q + pq2 - pq) - 6pq + 3pq2 =
3[-20 × 2 + (-20) × 2 - (-20)] - 6 × (-20) + 3 × 2 × (-20) =
3[-40 + (-40) + 20] - 6 × (-20) + 3 × 2 × (-20) =
3(-40 - 40 + 20) - 6 × (-20) + 3 × 2 × (-20) =
3(-80 + 20) - 6 × (-20) + 3 × 2 × (-20) =
3 × (-60) - 6 × (-20) + 3 × 2 × (-20) =
-180 + 120 + 6 × (-20) =
-180 + 120 + (-120) =
-180 + 120 - 120 =
-60 - 120 = -180
probability of you performing first is 1/13
after your team performs there are 12 teams left, so chance of the other team performing next is 1/12
chance of both happening = 1/13 * 1/12 = 1/156
Answer:
512x⁴y¹²
Step-by-step explanation:
its a cube so length x width x height
8xy⁴ times 8xy⁴ times 8xy⁴ is 512x³y¹²
Assuming that the center of each circle is at point C and D, then both have a radius of 7cm. We know that the formula for solving area of the circle is A=pi*r².
Then we solve area of once circle multiplied by two to get the total area of the given circles. The solution is shown below:
C1 area=3.1416*7²
C1 area=153.9384 cm²
Summation of the area of circle C and D is shown below:
Sum area=2*153.9384
Sum area=307.8768cm²
The answer is 98pi.
If i had a cylinder <span>If I cut it in right before the top, what do you think the cross section would look like?</span> answer a circle
