Which expression is NOT equivalent to 24 + 18?

If RT is 10 centimeters long, what is ST?

ioda

The answer is 6 centimeters

5 0

4 years ago

Read 2 more answers

2. If GFE~GJH, find the value of FG.

Alex73 [517]

Answer:

77 units

Step-by-step explanation:

Given two similar triangles.

Corresponding parts of similar figures have same ratio.

Use ratios to find the value of x:

(4x - 5)/(x + 7) = 35/12.5
(4x - 5)/(x + 7) = 14/5
5(4x - 5) = 14(x + 7)
20x - 25 = 14x + 98
20x - 14x = 98 + 25
6x = 123
x = 123/6
x = 20.5

Find the value of FG:

FG = 4*20.5 - 5 = 77

5 0

3 years ago

Use the written statement to construct a polynomial function that represents the required information.

timofeeve [1]

Answer:

not answering me ok mf bf ff

7 0

3 years ago

The Reviews editor for a certain scientific journal decides whether the review for any particular book should be short (1–2 page

Pavlova-9 [17]

Answer:

The probability that the selected review was submitted in Word format is 0.56.

Step-by-step explanation:

We are given that Data on recent reviews indicates that 50% of them are short, 30% are medium, and the other 20% are long. Reviews are submitted in either Word or LaTeX. For short reviews, 70% are in Word, whereas 50% of medium reviews are in Word and 30% of long reviews are in Word.

Let the probability that there are short reviews = P(S) = 0.50

The probability that there are medium reviews = P(M) = 0.30

The probability that there are long reviews = P(L) = 0.20

Let W = event that the reviews are submitted in either Word or LaTeX

So, the probability that short reviews are submitted in Word = P(W/S) = 0.70

The probability that medium reviews are submitted in Word = P(W/M) = 0.50

The probability that long reviews are submitted in Word = P(W/L) = 0.30

(a) The probability that the selected review was submitted in Word format is given by = P(W)

P(W) = P(S) $\times$ P(W/S) + P(M) $\times$ P(W/M) + P(L) $\times$ P(W/L)

= (0.50 $\times$ 0.70) + (0.30 $\times$ 0.50) + (0.20 $\times$ 0.30)

= 0.35 + 0.15 + 0.06

= 0.56

Hence, the probability that the selected review was submitted in Word format is 0.56.

(b) Now, if the selected review was submitted in Word format, the posterior probabilities of it being short is given by = P(S/W)

P(S/W) = $\frac{P(S) \times P(W/S)}{P(S) \times P(W/S)+P(M) \times P(W/M)+P(L) \times P(W/L)}$

= $\frac{0.50\times 0.70}{0.50\times 0.70+0.30\times 0.50+0.20\times 0.30}$

= $\frac{0.35}{0.56}$ = 0.625

Similarly, if the selected review was submitted in Word format, the posterior probabilities of it being medium is given by = P(M/W)

P(M/W) = $\frac{P(M) \times P(W/M)}{P(S) \times P(W/S)+P(M) \times P(W/M)+P(L) \times P(W/L)}$

= $\frac{0.30\times 0.50}{0.50\times 0.70+0.30\times 0.50+0.20\times 0.30}$

= $\frac{0.15}{0.56}$ = 0.268

Also, if the selected review was submitted in Word format, the posterior probabilities of it being long is given by = P(L/W)

P(L/W) = $\frac{P(L) \times P(W/L)}{P(S) \times P(W/S)+P(M) \times P(W/M)+P(L) \times P(W/L)}$

= $\frac{0.20\times 0.30}{0.50\times 0.70+0.30\times 0.50+0.20\times 0.30}$

= $\frac{0.06}{0.56}$ = 0.107.

7 0

3 years ago

Find an equation of a sphere if one of its diameters has endpoints (4, 1, 6) and (8, 3, 8).

AnnZ [28]

Answer:

The equation of a sphere with endpoints at (4, 1, 6) and (8, 3, 8) is $(x-6)^{2}+(y-2)^{2}+(z-7)^{2} = 6$ .

Step-by-step explanation:

Given the extremes of the diameter of the sphere, its center is the midpoint, whose location is presented below:

$C(x,y,z) = \left(\frac{4+8}{2},\frac{1+3}{2},\frac{6+8}{2}\right)$

$C(x,y,z) = (6,2,7)$

Any sphere with a radius $r$ and centered at $(h,k,s)$ is represented by the following equation:

$(x-h)^{2}+(y-k)^{2}+(z-s)^{2} = r^{2}$

Let be $(x,y,z) = (4,1,6)$ and $(h,k,s) = (6,2,7)$ , the radius of the sphere is now calculated:

$(4-6)^{2}+(1-2)^{2}+(6-7)^{2}=r^{2}$

$r = \sqrt{6}$

The equation of a sphere with endpoints at (4, 1, 6) and (8, 3, 8) is $(x-6)^{2}+(y-2)^{2}+(z-7)^{2} = 6$ .

5 0

3 years ago