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Anna [14]
4 years ago
10

Dimensions of a Box A large plywood box has a volume of . Its length is ft greater than its height, and its width is ft less tha

n its height. What are the dimensions of the box
Mathematics
1 answer:
cupoosta [38]4 years ago
8 0

Answer:

Few things are missing, they are volume of the box is 180 feet cube. Length is 9 feet greater than its height, and weight is 4 feet less than its height.

Step-by-step explanation:

Given, the volume of the box, V = 180 feet cube

Let the height of the box, h = x feet

Therefore, length is, l = ( 9+x ) feet

And width is, b = ( x-4) feet

so volume of the box is

V = l x b x h

$ 180= (x+9) \times (x-4) \times (x)$

$ x^3 +5x^2-36x -180 =0$

Factorizing we get

(x+5)(x-6)(x+6)=0

Therefore,

x = -5, -6, 6

Now since the height of the box cannot be negative, so taking the positive value of x, we get

Height of the box, h = x = 6 feet

Length , l = ( 9+x ) = 9+6 = 15 feet

Width , b = ( x-4) = 6-4 = 2 feet

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boyakko [2]

Answer:

\boxed{\sf \ \ 9x^2-18x-7 \ \  divided \ by \ (3x+1) \ is \ (3x-7) \ }

Step-by-step explanation:

Hello,

let's find a and b reals so that

9x^2-18x-7=(3x+1)(ax+b)

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we identify the terms in x^2

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we identify the terms in x

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so ti goes with a = 9/3 = 3, b = -7

so we can write

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so 9x^2-18x-7 \ divided \ by \ (3x+1) \ is \ (3x-7)

hope this helps

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Step-by-step explanation:

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Step-by-step explanation:

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