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4 years ago

Name four coplanar points

Mathematics

1 answer:

JulijaS [17]4 years ago

8 0

Answer:

Points Q, B, D, E

Step-by-step explanation:

By definition, coplanar points are points that share the same plane. In this case, the points that are on the parallelogram.

The points that are labeled inside the parallelogram are points Q, B, D, E, so they are the coplanar points.

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3 years ago

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Olin [163]

Answer:

m^2/n

Step-by-step explanation:

The following laws of exponent are useful to this problem:

$\displaystyle \large{ {(mn)}^{b} = {m}^{b} {n}^{b} } \\ \displaystyle \large{ {n}^{ - b} = \frac{1}{ {n}^{b} } }$

We are given the expression:

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } }$

Use the first law of exponent above.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{(8)( \frac{1}{4}) } {n}^{ ( - 4)( \frac{1}{4}) } } \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } {n}^{ - 1} }$

Make sure to recall the important necesscary fundamental math such as operation with negative numbers/integers, basic division, fraction, etc.

From the expression, apply the second law of exponent to n^-1.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n}^{1} } )} \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n} } )} \\$

Multiply m in.

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3 years ago

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irakobra [83]

Answer:

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Step-by-step explanation:

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3 years ago

its Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is Rs 15/m2. (Take n=3.14) flona

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Step-by-step explanation:

Given diameter of table (circular) =1.6m

radius =0.8m

area of circle = πr

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Cost of polishing table top = 15×2.0096

cost = 30.14m

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3 years ago