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scZoUnD [109]
2 years ago
15

2. If x represents a positive integer, find the solutions to the following inequalities. a. x − 15 < 20 b. x + 3 ≤ 15 c. −x &

gt; 2 d. x3 < 2 e. 3 − x4>2
Mathematics
1 answer:
vitfil [10]2 years ago
8 0

Answer:

jonga i-imeyile servos ingwenya

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The strength of a cable is proportional to the square of its diameter. If a 2-cm cable will support 800kg, how much will a 3-cm
xz_007 [3.2K]
Strength [is proportional to] d^2
strength1/(d1)^2 = strength2/(d2)^2
800kg/(2cm)^2 = strength2/(3cm)^2
strength2 = 800 kg * (3 cm)^2/(2 cm)^2
strength2 = 800 kg * 3^2/2^2
strength2 = 800 kg * 9/4
strength2 = 1800 kg
3 0
3 years ago
If you are going for best contents like myself, just pay a quick visit this web page everyday since it offers feature contents,
alexandr1967 [171]

Answer:

okay

Step-by-step explanation:

4 0
2 years ago
At the start of the recovery period, the waterbuck population contained only 140 individuals. The population had 0.67 births per
Sergio [31]

Answer:

the intrinsic growth rate of the population = 0.67 - 0.06 = 0.61 or 61%

Step-by-step explanation:

since populations increase exponentially, the same will happen here

in 5 years the population should be:

P₅ = P₀e°⁶¹ˣ⁵ = 140e°⁶¹ˣ⁵ = 2,956.15 ≈ 2,956

in 10 years the population will be:

P₁₀ = P₀e°⁶¹ˣ¹⁰ = 140e°⁶¹ˣ¹⁰ = 62,420.09 ≈ 62,420

when you are using exponential growth rates, we have to assume that r will always remain constant

6 0
3 years ago
En france en 1900 la taille moyennes des femmes etait de 1,54 m et celle des hommes de 1,66 m. Entre 1900 et 2010 ces tailles mo
frez [133]

Complete question :

En France, en 1900, la taille moyenne des femmes était de 1,54 m et celle des hommes de 1,66 m. Entre

1900 et 2010 ces tailles moyennes ont augmentées d'environ 5,55%.

Calculer, en mètres, l'arrondi au centième des tailles moyennes des femmes et des hommes en 2010.​

Répondre :

Femmes = 1,63

Hommes = 1,75 m

Explication étape par étape:

Étant donné que :

Taille moyenne en 1900:

Hommes = 1,66 m

Femmes = 1,54 m

Pourcentage d'augmentation de poids d'ici 2010 = 5,55%

1 + 5,55% = 1 + 0,0555 = 1,0555

D'où,

Taille des femmes en 2010:

1,0555 * 1,54 = 1,62547 = 1,63 m

Pour la taille des hommes en 2010:

1,0555 * 1,66 m = 1,75213 = 1,75 m

3 0
3 years ago
When graphing any equation what is a great fall back plan if you can't remember the learned procedure? (on all kinds of equation
miv72 [106K]

Answer:

GOOGLE :)

equation:

y=mx+b

m= slope (how steep the line is(negative is \ positive is /))

b= y intercept (where it is on the vertical line(up and down line))

step by step

1. locate y intercept and plotthe point

2.from that point use slop to find second point and plot

3 0
2 years ago
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