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777dan777 [17]
3 years ago
12

Help on 20, would be appreciated if there was a explanation as well

Mathematics
1 answer:
ra1l [238]3 years ago
6 0
For a two column proof, we want to start with the given information. From there, we will use various definitions, postulates, and theorems to fill in the rest.

Our two sets of given information are that Plane <em>M </em>bisects Line <em>AB </em>and that Line <em>PA</em> is congruent to Line <em>PB</em>.

We know from the definition of a bisector that it splits a line in two equal parts. Therefore, Line <em>AO</em> must be congruent to Line <em>BO</em>.

Now, we have two sides of a triangle that we have proved to be congruent to each other. From the image given in the original problem, we see that both triangles share Line <em>OP. </em>Line <em>OP</em> is congruent to Line <em>OP</em> through the reflexive property.

We now have proven that all three sides of the one triangle are congruent to the corresponding sides on the other triangle. Therefore, the triangles are congruent through the SSS theorem. 

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3 years ago
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
I need serious answers ppl keep putting those links
ohaa [14]

Answer:

Roman

Step-by-step explanation:

An easy way to solve this is looking at whether the line has a positive or negative slope. We read graphs from left to right so <u>if the line is increasing from left to right, it has a positive slope while a line decreasing from left to right has a negative slope</u>. Since the line shown is decreasing from left to right, it will have a negative slope and Roman is the only one out of the two that shows a negative slope. To check to see if he's correct, we can check the y-intercept. The y-intercept of the line is 8 and Roman also has 8 written in the expression. Hence, meaning Roman is correct.

Best of Luck!

7 0
3 years ago
Can someone help me answer this question asap
dsp73
The volume is 134.4 and surface area is <span>276.8 hope this helps ! ^_^ dnt forget to mark me brainiest</span>
7 0
3 years ago
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