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2 years ago

Help on 20, would be appreciated if there was a explanation as well

Mathematics

1 answer:

ra1l [238]2 years ago

6 0

For a two column proof, we want to start with the given information. From there, we will use various definitions, postulates, and theorems to fill in the rest.

Our two sets of given information are that Plane M bisects Line AB and that Line PA is congruent to Line PB.

We know from the definition of a bisector that it splits a line in two equal parts. Therefore, Line AO must be congruent to Line BO.

Now, we have two sides of a triangle that we have proved to be congruent to each other. From the image given in the original problem, we see that both triangles share Line OP. Line OP is congruent to Line OP through the reflexive property.

We now have proven that all three sides of the one triangle are congruent to the corresponding sides on the other triangle. Therefore, the triangles are congruent through the SSS theorem.

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An object is dropped from a bridge and allowed to freefall to the ground. The height of the object over time can be modeled usin

kkurt [141]

Answer:

t = 3 seconds

Step-by-step explanation:

We have the equation, as a function of time, that describes the height of the object that is dropped from the bridge.

The equation is:

$h (t) = 144 - 16t ^ 2$

Where t is the time in seconds and h is the height in feet.

To know how long it takes the object to fall to the ground we do h (t) = 0 and solve for t.

So:

$0 = 144 - 16t ^ 2\\\\16t ^ 2 = 144\\\\t ^ 2 = \frac{144}{16}\\\\t ^ 2 = 9\\\\t_1 = 3\\t_2 = -3$

We take the positive solution.

Therefore the object takes 3 seconds to reach the ground

4 0

3 years ago

Read 2 more answers

Without solving, determine whether the equation 3 - (x + 1) = 2 - x has one solution, no solutions, or infinitely many solutions

Rudiy27

Answer:

infinite

Step-by-step explanation:

3 0

2 years ago

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}$

when will it reach the ground level? let's set s(t) = 0

$\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}$

part B) check the picture below

5 0

2 years ago

Need help with using the graph to find the numbers

iren [92.7K]

Answer:

Need help with using the graph to find the numbers

Assignment is about evaluating composition of functions from graphs anything helps

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2 years ago

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The mass of a proton is approximately 1.67 x 10−24, and the mass of an electron is approximately 9.11 x 10−28. Find the approxim

svetoff [14.1K]

1.67x[10^(-20)] 1.67x[10^(-24+28)]
--------------------- = -------------------------- =
9.11x[10^(-28)] 9.11

.183315(10^4)=1833.15

The proton mass is about 1833 times an electron mass

Hope this helps!

5 0

3 years ago

Read 2 more answers