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umka21 [38]
3 years ago
8

5) What is the smallest number by which 1323 must be multiplied so that the product is a perfect

Mathematics
1 answer:
Westkost [7]3 years ago
5 0

Answer:

the smallest number is 7

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46. Order these numbers from least to greatest:<br> 1/2, 0.4, 1/3, 1/5
e-lub [12.9K]

Answer:

1/5, 1/3, 0.4, 1/2

Step-by-step explanation:

1/5 = 0.2

1/3 = 0.33

1/2 = 0.5

4 0
2 years ago
Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=
luda_lava [24]

Let f(x) = x^3 - 2x - 2. Then differentiating, we get

f'(x) = 3x^2 - 2

We approximate f(x) at x_1=2 with the tangent line,

f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18

The x-intercept for this approximation will be our next approximation for the root,

10x - 18 = 0 \implies x_2 = \dfrac95

Repeat this process. Approximate f(x) at x_2 = \frac95.

f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}

Then

\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}

Once more. Approximate f(x) at x_3.

f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}

Then

\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}

Compare this to the actual root of f(x), which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0
2 years ago
What is the quotient two 1/5÷-1/10
VladimirAG [237]
The answer should be -2 hope this helps /)
5 0
3 years ago
Read 2 more answers
Kai took five tests this semester. His scores are listed below.
Travka [436]

Answer:

3.2 is the answer. Your welcome

3 0
3 years ago
Which equation, in point-slope form, passes through (-2, 4) and has a slope of 3?
MA_775_DIABLO [31]

Answer:

B. Y-4 =3(x+2)

7 0
3 years ago
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