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Daniel [21]
3 years ago
15

Evaluate g(x)=6 when x = -3,0, and 4.

Mathematics
1 answer:
iVinArrow [24]3 years ago
5 0

Answer:

-18 = g(-3) \\0 = g(0) \\ 24 = g(4)

Step-by-step explanation:

6 \times 4 = 24 \\ 0 \times 6 = 0 \\  -3 \times 6 =  -18

I hope this helps, and as always, I am joyous to assist anyone at any time.

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Wey wey drops a pencil in her cup and notices that it only fits diagonally. the pencil is 9 centimeters long and the cup is 7 ce
vesna_86 [32]

Answer:

5.656854249 cm

Step-by-step explanation:

Use the Pythagorean theorem to solve this (assuming that the bottom of the cup is a right angle). a^{2} +b^{2} =c^{2}. a and b are sides, and c is the hypotenuse.

The length of the pencil would be the hypotenuse (c), and how tall the cup is (7 cm) would be one of the sides (a).     The diameter of the cup, would be the other side (b).

Plug this into the Pythagorean theorem to get the equation: 7^{2} +b^{2} =9^{2}. From here, we can find the diameter of the cup by isolating b - remove everything from the left side, but remember, what you do to one side you must do to the other.

First, solve all of the exponents: 49+b^{2}=81

Second, subtract 49 from both sides: b^{2}=32 This cancels out the 49 on the left.

Lastly, square root both sides: x=5.656854249 This cancels out the exponent on the left.

In conclusion, the diameter of the cup is 5.656854249 centimeters.

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Brian completed 34 free throws and missed 16.
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It is 46 if you divide 34 by 16 you get 2.125 then divide 100 by 2.125 and you get 47.05 the 0 means go down if you are rounding which brings it to 46

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Evaluate the expression when c=21 and d=4.<br> c-5d
vekshin1

\huge \boxed{\mathfrak{Question} \downarrow}

  • Evaluate the expression when c = 21 and d = 4, c - 5d = ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

Given,

  • c = 21
  • d = 4
  • c - 5d = ?

Let's solve it now :-

\sf \: c - 5d \\  \\  \sf \: Substitute \: the \: values \: of \: c \: and \: d \\  \\ \sf c - 5d \\  \rightarrow \sf(21) - 5(4) \\ \sf  \rightarrow21 - 20 \\  =    \boxed{\boxed{\bf \: 1}}

  • The value of the expression is <em><u>1</u></em><em><u>.</u></em>
6 0
3 years ago
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