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beks73 [17]
3 years ago
9

Who wants to be my best friend in brainly?

Mathematics
2 answers:
Eddi Din [679]3 years ago
8 0

Answer: Sure, man! Why not? ^^

Shkiper50 [21]3 years ago
5 0

Me

Please

If you want

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Q is the midpoint PR.If PQ =2x and QR= x+8.What is PQ?
vovikov84 [41]

2x=x+8

Subtract x on both sides

X=8

So PQ=8

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3 years ago
What does g in gmdas stand for
Step2247 [10]

Answer:

IM NOT SURE WHAT you mean

Step-by-step explanation:

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4 years ago
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At a pressure 41 kPa, the gas in a cylinder has a volume of 16 liters. Assuming temperature remains the same, if the volume of t
DiKsa [7]
If temperature (T) and amount of gas (n) remain constant, but pressure (P) and volume (V) change, then the ideal gas law: PV = nRT becomes
P1V1 = P2V2 --> (41)(16) = P2 (4)
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What is the decimal value of 5/6
Alex787 [66]

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0.83

Step-by-step explanation:

The 3 keeps going on and on and on :)

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3 years ago
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A stereo system is being installed in a room with a rectangular floor measuring 15 feet by 11 feet and a 10​-foot ceiling. The s
Likurg_2 [28]

Answer:

Shortest length of wire = 28.60 feet

Step-by-step explanation:

<u>Distances In Rectangular Objects </u>

If we want to go from one point in space to another one, the shortest possible distance is through a line. But if we are not allowed to, we must try to use as many direct paths as possible to minimize the distance.

In our case, the minimum distance will be going right from one corner to the other through the air, but we must use walls and floor. So our choices are limited to shorten the distance as much as possible by taking paths from corners whenever it's possible.

Starting from the corner where the stereo system is located, we must try to reach the other corner by using one of these options

  • Cross the floor by its diagonal and then go right to the other corner in the ceiling
  • Cross one wall by its diagonal and then go to the other corner. It can be done for each adjacent wall to the stereo system.

If we try the first option first, the diagonal of the floor measures

\displaystyle \sqrt{15^2+11^2}

And now we reach the other corner, traveling a total distance of

\displaystyle L_1\sqrt{15^2+11^2}+10

\displaystyle L_1=28.60\ {ft}

Trying one of the adjacent walls

\displaystyle L_2=\sqrt{15^2+10^2}+11

\displaystyle L_2=29.028\ feet

And the final option is

\displaystyle L_3=\sqrt{10^2+11^2}+15\ feet

\displaystyle L_3=29,87\ feet

We can see the first is the shortest distance, so to reach the speaker we must cross the floor by its diagonal and the go up to the speaker

Note: Each of the options analyzed have a identical counterpart by taking the opposite side first. For example, the path floor-wall could have been done as wall-ceiling, with identical results

4 0
3 years ago
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