Question

The sum of two-thirds of a number and one-fourth of the number exceeds five-sixths of that number by two. . . Which equation could be used to determine the number?. A) 2/3 +1/4 n = 5/6n + 2. B) 2/3n + 1/4 = 5/6n + 2. C) 2/3n + 1/4n = 5/6n + 2

Answer 1

Answer:

C) $\frac{2}{3} n + \frac{1}{4} n = \frac{5}{6} n + 2$

Explanation:

Assume that the number is n

For the left hand side:

Two thirds of the number is $\frac{2}{3} n$

one fourth of the number is $\frac{1}{4} n$

The sum means that we will add them

Therefore, the left hand-side is:

$\frac{2}{3} n$ + $\frac{1}{4} n$

For the right hand side:

five sixth of the number is $\frac{5}{6} n$

two is 2

exceeds means that we will add

Therefore,the right-hand side is:

$\frac{5}{6} n$ + 2

Combining the two sides, we will get the expression:

$\frac{2}{3} n + \frac{1}{4} n = \frac{5}{6} n + 2$

Hope this helps :)

Answer 2

Answer: 
C ) 2/3 n + 1/4 n = 5/6 n + 2
Thank you.