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aksik [14]
2 years ago
9

You pick cards one at a time without replacement from an ordinary deck of 52 playing cards. what is the minimum number of cards

you must pick in order to guarantee that you get a pair?a. a pair (for example, two kings or two 5s). b. three of a kind (for example, three 7s).
Mathematics
1 answer:
pishuonlain [190]2 years ago
5 0

Answer:

a) 2

b) 3

Step-by-step explanation:

supposing you got lucky or the deck wasn't shuffled, the first 2 cards could very well be a pair (or the first 3 a three of a kind)

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Wrong answers will be reported ​
PIT_PIT [208]

The solution to the equation is p = 1/3 and q = undefined

<h3>How to solve the equation?</h3>

The equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

The best way to solve the above equation is by the use of a graphing calculator i.e. graphically

However, it can be solved algebraically too (to some extent)

Recall that the equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

Split the equation

So, we have

p^2 - 2qp + 1/q = 0

p - 1/3 = 0

Solve for p in p - 1/3 = 0

p = 1/3

Substitute p = 1/3  in p^2 - 2qp + 1/q = 0

So, we have

(1/3)^2 - 2q(1/3) + 1/q = 0

This gives

1/9 - 2/3q + 1/q = 0

This gives

2/3q + 1/q = -1/9

Multiply though by q

So, we have

2/3q^2 + 1 = -1/9q

Multiply through by 9

6q^2 + 9 = -q

So, we have

6q^2 + q + 9 = 0

Using the graphing calculator, we have

q = undefined

Hence. the solution to the equation is p = 1/3 and q = undefined

Read more about equations at:

brainly.com/question/13763238

#SPJ1

5 0
1 year ago
You have two summer jobs. At the Burger Palace you earn $8 per hour. At the community center you teach soccer clinics for $10 pe
SIZIF [17.4K]
The complete question in the attached figure
 we have that
x-------------> number of hours works at Burger Palace -----> <span>$8
</span>y-------------> number of hours works at <span>community center</span> -----> $10
<span>
8x+10y>=200

using a graph tool
see the attached figure

the answer is the option B
</span><span>
</span>

8 0
3 years ago
In a geometric sequence, a4 = 54 and a7 = 1,458. what is the 12th term? <br><br> answer: B) 354,294
slamgirl [31]

Option B:

The 12th term is 354294.

Solution:

Given data:

a_4=54 and a_7=1458

To find a_{12}:

The given sequence is a geometric sequence.

The general term of the geometric sequence is a_n=a_1\ r^{n-1}.

If we have 2 terms of a geometric sequence a_n and a_k (n > K),

then we can write the general term as a_n=a_k\ r^{n-k}.

Here we have a_4=54 and a_7=1458.

So, n = 7 and k = 4 ( 7 > 4)

a_7=a_4\ .\ r^{7-4}

1458=54\ . \  r^3

This can be written as

$r^3=\frac{1458}{54}

$r^3=27

$r^3=3^3

Taking cube root on both sides of the equation, we get

r = 3

a_{12}=a_7\ .\ r^{12-7}

     =1458\ .\ r^5

     =1458\ .\ 3^5

a_{12}=354294

Hence the 12th term of the geometric sequence is 354294.

7 0
2 years ago
3 decreased by the difference of h and 5
sergejj [24]
Is there a picture that goes with this problem?
8 0
1 year ago
Allan and Dave bowl together and their combined total score for one game was 375 points. Allan’s score was 60 less than twice Da
Bess [88]
A system of equations is:
B ) 
x + y = 375
x = 2 y - 60
We will solve this system:
2 y - 60 + y = 375
3 y = 435
y = 435 : 3
y = 145
x = 375 - 145
x = 230
Allan`s score was 230 and Dave`s score was 145.

6 0
2 years ago
Read 2 more answers
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