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bija089 [108]
3 years ago
13

Help: Simplifying inside parenthesis first

Mathematics
1 answer:
Ne4ueva [31]3 years ago
3 0

Answer:

4th one

Step-by-step explanation:

a^-2 goes down and become a^2 and

{a}^{2}  \times  {a}^{2}  =  {a}^{4}

b^-1 goes up and become b

{b}^{2}  \times  {b}^{1}  =  {b}^{3}

that why answer is 4th...mark me brainliest please

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Read 2 more answers
How to solve X - 1v+ 4 + 7y - 3
Nostrana [21]
The first step to solving this is to remember our mathematical rules. They state that when the term has a coefficient of -1,, the number doesn't have to be written but the sign needs to remain. This will change the expression to the following:
x - v + 4 + 7y - 3
Now subtract the numbers 4 and 3 from each other.
x - v + 1 + 7y 
Since this expression cannot be simplified any further,, the correct answer to your question would be x - v + 1 + 7y.
Let me know if you have any further questions.
:)
3 0
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