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3 years ago

Help: Simplifying inside parenthesis first

Mathematics

1 answer:

Ne4ueva [31]3 years ago

3 0

Answer:

4th one

Step-by-step explanation:

a^-2 goes down and become a^2 and

${a}^{2} \times {a}^{2} = {a}^{4}$

b^-1 goes up and become b

${b}^{2} \times {b}^{1} = {b}^{3}$

that why answer is 4th...mark me brainliest please

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Use the table below to find f ( 4) - f (0) + f(-8), Choose your correct response from the options below.

marshall27 [118]

Answer:

-4f

Step-by-step explanation:

Hi! Let's work on simplifying this.

f(4) = 4f

f(0) = 0, because anything x 0 is 0

f(-8) = -8f

Our equation is 4f + -8f

We can get rid of the plus negative...

4f - 8f

So we get:

-4f

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Is 7/0 an irrational, rational , or not a real number

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Complete the square 2x2- 12x+ 26 = 10

Mariana [72]

$2x^2-12x+26=10\ \ \ | subtract\ 10\\\\
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x^2-6x+8=0\\\\
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d=-3\\
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After\ completing\ the\ square:\\
(x-3)^2-1=0$

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4 years ago

In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=83°, and RS = 7 feet. Find the length of SQ to the nearest tenth of a foot.

Simora [160]

Answer:

x ~0.9

Step-by-step explanation:

To solve for (x) in the given right triangle, use the trigonometric ratios, which are the following,

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

Each of the sides of a triangle is named with respect to the given angle. In this problem, one is given the side opposite to the given angle, and the side adjacent to it. Use the ratio of tangent (tan) to solve for the unknown side.

$tan(83)=\frac{7}{x}$

Manipulate the equation so that it is solved for (x),

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x ~ 0.859

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3 years ago

A family is having a pool built in their backyard. Their yard is rectangular and measures 14x by 19x and the pool is circular wi

valentina_108 [34]

You want to find the area left over after the pool is built, so subtract the area of the pool from the area of the yard.

Area of Yard= Base x Height = 14x*19x = 266x^2
Area of Circle= Pi x Radius^2 = (6x)^2*pi = 36x^2*pi

Now subtract the two areas:
266x^2-(36^2*pi)
266x^2-36x^2*pi

Take 2x^2 as a common factor:
2x^2(133-18pi)

D: <span>2x^2(133-18pi)

Hope this helps :)</span>

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4 years ago