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dimaraw [331]
2 years ago
15

Help! I’ll give extra points:)

Mathematics
1 answer:
Fofino [41]2 years ago
3 0

Answer:

if I'm not wrong I think it's B

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What is the answer for 30/-31?
mart [117]

Answer:

-0.96774193548

Step-by-step explanation:

kind a mouth full

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3 years ago
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

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so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
Really stuck help <br> The picture below is the problem
iren [92.7K]

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Step-by-step explanation:

figure one

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figure 2

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The answer would 50.
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