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Setler [38]
3 years ago
15

Which of ordered pairs is not a function ?

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0
Answer:4)\\\\because\\(2;\ 3)\to x=2\ and\ y=3\\(2;\ 4)\to x=2\ and\ y=4\\\\for\ this\ same\ "x"\ y=3\ and\ y=4\\\\and\\\\(4;\ 5)\to x=4\ and\ y=5\\(4;\ 6)\to x=4\ and\ y=6\\\\for\ this\ same\ "x"\ y=5\ and\ y=6
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Which bacteria sample (A or B) had a smaller initial population? What was that value?
zubka84 [21]

Answer:

B has a smaller initial population of 500

Step-by-step explanation:

Given

See attachment for complete question

Required

The bacteria with the smaller initial population

The initial population is at x = 0

For bacteria A;

A(x) = 600 when x = 0

For bacteria B, we have:

B(x) = 500(2)^x

Substitute 0 for x

B(x) = 500(2)^0

B(x) = 500*1

B(x) = 500

So; when x = 0

A(x) = 600 and B(x) = 500

Because; 500 < 600

We can conclude that B has a smaller initial population of 500

4 0
2 years ago
I need to write an algebraic expression that includes 2 constatants, 2 variables, and 2 different operations. It also need it in
belka [17]

Answer:

An example would be

(x+3)-(y+12)

The two constants are 3 and 12 (I'm assuming you meant "constant" as in the number that stands by itself and not "constatant" lol)

The two variables are x and y

The two operations are addition and subtraction

In words you could say "the quantity of x plus three minus the quantity of y plus twelve"

3 0
3 years ago
PLEASE HELP ME :(( i tried 12 as the answer and it’s wrong
AnnZ [28]

I think its 1/6

I'm not sure tho

u take the bottom and subtract it by the top then multiply

6 0
2 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME OUT PLEASE I WOULD APPRECIATE IT VERY MUCH
tatyana61 [14]

Answer:Decreasing

Step-by-step explanation:

Focus only on the 8-10 interval for x. Note that for x=8 , y=1, for x=9, y=0 and for x=10, y=-1. Y is obviously decreasing for 8 .

6 0
3 years ago
Which of the following is the simplified form of fifth root of x times the fifth root of x times the fifth root of x times the f
Juliette [100K]

Answer:

\large\boxed{x^\frac{4}{5}}

Step-by-step explanation:

\sqrt[n]{a}=a^\frac{1}{n}\Rightarrow\sqrt[5]{x}=x^\frac{1}{5}\\\\\sqrt[5]{x}\cdot\sqrt[5]{x}\cdot\sqrt[5]{x}\cdot\sqrt[5]{x}=x^\frac{1}{5}\cdot x^\frac{1}{5}\cdot x^\frac{1}{5}\cdot x^\frac{1}{5}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=x^{\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}}=x^\frac{4}{5}

4 0
3 years ago
Read 2 more answers
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