Which of ordered pairs is not a function ?

1 answer:

4 0

$Answer:4)\\\\because\\(2;\ 3)\to x=2\ and\ y=3\\(2;\ 4)\to x=2\ and\ y=4\\\\for\ this\ same\ "x"\ y=3\ and\ y=4\\\\and\\\\(4;\ 5)\to x=4\ and\ y=5\\(4;\ 6)\to x=4\ and\ y=6\\\\for\ this\ same\ "x"\ y=5\ and\ y=6$

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What is this please help?

mestny [16]

Answer:

y = 2/3x - 1

Step-by-step explanation:

The simpliest way to determine the slope of the line is to see the rise over run of the line. In this case, we are given two points which are at (0, -1) and (3,1)

By calculating rise of run, we can see that the starting point goes up by 2 units, from -1 to 1 and goes to the right 3 units, from 0 to 3

In this case, that means we have a slope of 2/3x.

The +b plays into the y-intercept of the line, which is actually the same of one of our points: (0,-1)

Since this number is a negative, it would actually be y = (2/3)x + (-1) which is the same as y=2/3x - 1

7 0

2 years ago

Write 7.630 in word form.

Maru [420]

Answer:

seven and six hundred thirty thousandths

Step-by-step explanation:

the decimal point is when you say and when reading it

4 0

3 years ago

What is the answer to the problem 5x-2=2x-3

LUCKY_DIMON [66]

First, isolate the x:

5x-2x= 2-3

Then solve!

3x= -1
x= -1/3

Hope this helps!

4 0

3 years ago

What is the length of the major axis of the ellipse (x-7)^2/4+(y+3)^2/16=1

yuradex [85]

$\bf \begin{array}{llll}
\cfrac{(x-{{ h}})^2}{{{ a}}^2}+\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1\\\\ \cfrac{(x-{{ h}})^2}{{{ b}}^2}+\cfrac{(y-{{ k}})^2}{{{ a}}^2}=1
\end{array}\quad 
\begin{cases}
\textit{major axis}=a+a\\
a=\textit{the larger denominator}\\
b=\textit{smaller denominator}
\end{cases}\\\\
-----------------------------\\\\
\cfrac{(x-7)^2}{4}+\cfrac{(y+3)^2}{16}=1\implies \cfrac{(x-7)^2}{2^2}+\cfrac{(y+3)^2}{4^2}=1\quad 
\begin{cases}
a=4\\
b=2
\end{cases}$