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2 years ago

The reflection of a Quadrant II point is located in Quadrant I. Assuming no error was made, what kind of reflection occurred?

Mathematics

2 answers:

V125BC [204]2 years ago

7 0

Answer:

A reflection across the y-axis.

Step-by-step explanation:

If it was across the x-axis, the point would have gone into Quadrant III.

The y-axis is vertical, and it was moved into Quadrant I from Quadrant II making it a vertical reflection which is a reflection from the y-axis.

gizmo_the_mogwai [7]2 years ago

3 0

Answer:

A reflection across the y- axis

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y) → (-x, y)

A point in the second quadrant (- x, y)

Under reflection in the y- axis is (x, y) ← point in first quadrant

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3 years ago

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2 years ago

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The sum of the lengths of two opposite sides of the circumscribed quadrilateral is 12 cm, the length of a radius of the circle i

nasty-shy [4]

Answer:

60cm^2

Step-by-step explanation:

We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...

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3 years ago

Find the value of x.

mixas84 [53]

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2 years ago

Can someone walk me through this?

Diano4ka-milaya [45]

So you can set up proportion.

$\dfrac{7.5\ \text m}{76^\circ} = \dfrac C{360^\circ}$

Here, you need to solve for C.

You can do that by multiple both sides by 360 and then you should get $360^\circ\cdot\dfrac{7.5\ \text m}{76^\circ} = C \approx \boxed{35.526\ \text m}$

Hope this helps.

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2 years ago