Answer:
3/12 and 2/12 cannot
Step-by-step explanation:
D seems to have the possibility of having the largest range.
Cotxcos2x = 2cotx
cos2x = 2cotx/cotx
cos2x = 2
cos2x = 2cos²x - 1
2cos²x - 1 = 2
2cos²x = 2+1
2cos²x = 3
cos²x = 3/2
√cos²x = plus minus √(3/2)
cosx = plus minus √(3/2)
3 and 4 are regular polygon and 5 is not
Notice how the problem states that the marbles are being placed back into the bag which means you are on the right track but the denominators are the same.
3/11 times 3/11 times 5/11 which gives us the answer of 45/1131