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Kamila [148]
3 years ago
6

Help me pls fast ASAP

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0

I think the answer is the last one.

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Product of 2 to the second power and the fourth multiple of 10
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160

Step-by-step explanation:

2² is 4 and the fourth multiple of 10 is 40.

Multiply those numbers together, and you get 160.

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A jar contains 5 purple, 6 yellow, 8 green, and 5 orange jellybeans. What is the probability of selecting a yellow jellybean fol
Oksana_A [137]

Answer:

\frac{5}{96}

Step-by-step explanation:

At the beginning, the jar contains the  following beans:

5 purple

6 yellow

8 green

5 orange

Therefore, the total number of jellybeans in the jar tha beginning is:

n=5+6+8+5=24

The number of yellow beans at the beginning is

y=6

Therefore, the of selecting a yellow jellybean at the beginning is

p(y)=\frac{y}{n}=\frac{6}{24}=\frac{1}{4}

After selecting this yellow bean, the yellow bean it is replaced in the jar, so the number of total beans is still n = 24.

And the number of purple beans inside is

p=5

So, the probability of selecting a purple bean at the 2nd attempt is

p(p)=\frac{5}{24}

Therefore, the combined probability of selecting a yellow jellybean followed by a purple one is

p(yp)=p(y)\cdot p(p)=\frac{1}{4}\cdot \frac{5}{24}=\frac{5}{96}

3 0
3 years ago
Mike is redecorating his office’s conferences rooms. When they were last painted it took 20 pints of paint. The paint he is usin
german

Previously the volume of paint consumed was: 20 pints

New paint is available in unit of liters.

since, 1 pint = 0.47 liter

20 pint = 9.46 liters (10 liters approx.)

Mike will need to buy 10 liters of paint.

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3 years ago
A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with A random s
evablogger [386]

Complete Question

A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with\sigma^2=1000. A random sample of 12 sample specimens has a mean compressive strength of \=x=3207psi. Round your answers to 1 decimal place. (a) Calculate the 95% two-sided confidence interval on the true mean compressive strength of concrete.

Answer:

CI=(3189.1,3224.9)

Step-by-step explanation:

From the question we are told that:

Sample size n=12

Standard deviation \sigma^2=1000psi^2\\\sigma=\sqrt{1000} \\\sigma=31.6

Sample mean \=x=3207

Confidence level =95%

\alpha=100-95\\\alpha=0.05 significance level

From table \alpha 0.05

Gives

Z_c=1.96  

Generally the equation for confidence interval is mathematically given by

CI=(\=x-\frac{z_c*\sigma}{\sqrt{n} } ),\=X+\frac{Z_C*\sigma}{\sqrt{12} })

CI=(3207-\frac{1.96*31.6}{\sqrt{12} } ),3207+\frac{1.96*31.6}{\sqrt{12} })

CI=(3189.1,3224.9)

6 0
2 years ago
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