Question

Same as before this test... is just driving me crazy I'm blowing all my points through these so...

Answer 1

Step-by-step explanation:

It's a right triangle with one of the angles being 60°. This means that the leftover angle is 30°. This allows me to use the attached screenshot as a reference, so please check it out if you want to understand how to easily solve those types of equations in the future. Anyway, we can specify the hypotenuse as $a$ .

First, let's calculate the value of $y$.

$a$ = $10\sqrt{3}$

$y$ = $\frac{a}{2}$

$y$ = $\frac{10\sqrt{3} }{2}$

$y$ = $5\sqrt{3}$

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Now, let's get to $x$

$a$ = $10\sqrt{3}$

$x$ = $\frac{a\sqrt{3} }{2}$

$x$ = $\frac{10 \sqrt{3} * \sqrt{3}}{2}$

$x$ = $\frac{10 * 3}{2}$

$x$ = $\frac{30}{2}$

$x$ = $15$

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$x$ = $15$ and $y$ = $5\sqrt{3}$

Answer 2

Answer and Step-by-step explanation:

For this, you would need to use the trigonometric function Sine and cosine.

The trig equations are:

sin(θ) = $\frac{opposite - side}{hypotenuse}$

cos(θ) = $\frac{adjacent-side }{hypotenuse}$

Let's start with Sine:

sin(60) = $\frac{x}{10\sqrt{3} }$

Multiply both sides of the equation by $10\sqrt{3}$.

$10\sqrt{3} (sin(60)) = x$

Input into calculator and solve.

x = 15

Now for Cosine:

cos(60) = $\frac{y}{10\sqrt{3} }$

Multiply both sides of the equation by $10\sqrt{3}$.

$10\sqrt{3} (cos(60)) = x$

Input into calculator and solve.

y = $5\sqrt{3}$

x = 15

y = $5\sqrt{3}$

These are the answers.

I hope this helps!

#teamtrees #PAW (Plant And Water)