All categories

3 years ago

The total price for 7 movie tickets is 92.40 . If each ticket costs the same amount, how much does one movie ticket cost?

Mathematics

2 answers:

horsena [70]3 years ago

8 0

Answer:

$13.20

Step-by-step explanation:

total cost of tickets = $92.40

total number of tickets = 7

cost of each ticket

= total cost of tickets ÷ total number of tickets

= 92.40 ÷ 7

= $13.20

hope this helps

Solnce55 [7]3 years ago

5 0

Answer:

$13.2 for 1 movie ticket

Step-by-step explanation:

7m = 92.40

(divide all by 7)

m = 13.3

You might be interested in

Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

6 0

3 years ago

Area A, equals the product of b and h divided by 2, slove for h

gizmo_the_mogwai [7]

A = bh/2
2a = bh
2a/b = h

h = 2a/b

7 0

3 years ago

Need help on this question i dont get it ima be posting some more but i need help on this on first

Anuta_ua [19.1K]

Answer:

The answer is B.

Step-by-step explanation:

Its B because in the problem it says $12 per yard which means it would be 12y. The 40 Rupesh already had so just add it and it would be 12y+ 40. The key word "At least" results into the sign being greater than or equal to. So the final answer would be 12y+40 $\geq$ 148.