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topjm [15]
3 years ago
11

2.The mean area of several thousand apartments in a new development is advertised to be 1,100 square feet. A consumer advocate h

as received numerous complaints that the apartments are smaller than advertised. A state building inspector is sent out to measure a sample of apartments. State the null and the alternative hypothesis to test this claim.
Mathematics
1 answer:
KiRa [710]3 years ago
4 0

Answer:

Null Hypothesis, H_0 : \mu = 1,100 square feet

Alternate Hypothesis, H_A : \mu < 1,100 square feet

Step-by-step explanation:

We are given that the mean area of several thousand apartments in a new development is advertised to be 1,100 square feet.

A consumer advocate has received numerous complaints that the apartments are smaller than advertised.

<u><em>Let </em></u>\mu<u><em> = mean area of several apartments.</em></u>

So, Null Hypothesis, H_0 : \mu = 1,100 square feet

Alternate Hypothesis, H_A : \mu < 1,100 square feet

Here, <u>null hypothesis states that</u> the mean area of apartments are same as advertised.

On the other hand, <u>alternate hypothesis states that</u> the mean area of apartments are smaller than advertised.

So, this would be the appropriate null and the alternative hypothesis to test this claim.

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we have been asked to perform (6.496*10^{-6})\div (2.8*10^5)

The given expression can be written as

\frac{(6.496*10^{-6})}{2.8*10^5}

Now it can be re-written as below

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3 years ago
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Explanation:

First, write the formula:
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He will get 20 cups of punch.

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