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Greeley [361]
3 years ago
7

The area of a rectangle in 24 square units. A diagonal drawn from one corner to another divides the rectangle into two right tri

angles.
What is the area of the shaded triangle?

Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0

Hello from MrBillDoesMath!

Answer:

12


Discussion:

The two triangles shown are congruent by the SAS postulate so the area of a single triangle is one-half that of the rectangle.  That is,

Area = (1/2) * 24 = 12


Thank you,

MrB

Strike441 [17]3 years ago
3 0

Answer:

<em> (1/2) * 24 = 12</em>

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Factor Completely: 10x + 15
tankabanditka [31]

Answer:

5(2x + 3)

Step-by-step explanation:

10x + 15 \\  \\  = 2 \times 5 \times x + 3 \times 5 \\ ( take \: common \: factors \: out )\\  = 5(2 \times x + 3) \\  \\  = 5(2x + 3)

3 0
2 years ago
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Pls show work I need the work. Thx
Ainat [17]
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5 0
3 years ago
Let L be the line parametrized by x = 2 + 2t, y = 3t, z = −1 − t. (a) Find a linear equation for the plane that is perpendicular
Elden [556K]

Answer:

Step-by-step explanation:

Given that L is a line parametrized by

x = 2 + 2t, y = 3t, z = −1 − t

The plane perpendicular to the line will have normal as this line and hence direction ratios of normal would be coefficient of t in x,y,z

i.e. (2,3,-1)

So equation of the plane would be of the form

2x+3y-z =K

Use the fact that the plane passes through (2,0,-1) and hence this point will satisfy this equation.

2(2)+3(0)-(-1) =K\\K =5

So equation is

2x+3y-z =5

b) Substitute general point of L in the plane to find the intersecting point

2(2+2t)+3t-(-1-t) =5\\4+8t+1=5\\8t=0\\t=0\\(x,y,z) = (2,0,-1)

i.e. same point given.

3 0
3 years ago
What is the angle in part c? Thank you.
Anton [14]
It looks like an equilateral triangle if I am correct then angle C equals 60 degrees
7 0
3 years ago
Find x and y on triangle<br>Also the degree is 30 and the other thing is 7sqrt3​
nydimaria [60]

Answer:

y =7

x =14

Step-by-step explanation:

Since this is a right triangle we can use trig functions

tan 30 = opp /adj

tan 30 = y/ 7 sqrt(3)

7 sqrt(3)  tan 30 = y

7 sqrt(3) * 1/ sqrt(3) =t

7 =y

sin 30 = opp/ hyp

sin 30 = 7/x

x sin 30 =7

x = 7/ sin 30

x = 7 / 1/2

x = 14

6 0
3 years ago
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