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1 year ago

10

Type SSS, SAS, ASA, SAA, or HL to

1 answer:

Phoenix [80]1 year ago

6 0

Answer:

ASA

Step-by-step explanation:

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(W+4)(3w-2) please solveeed

Shkiper50 [21]

Step-by-step explanation:

${:}\longrightarrow$ $\sf (w+4)(3w-2)$

${:}\longrightarrow$ $\sf w(3w-2)+4 (3w-2)$

${:}\longrightarrow$ $\sf 3w^2-2w+12w-8$

${:}\longrightarrow$ $\sf 3w^2+10w-8$

7 0

3 years ago

Read 2 more answers

The junior class is selling printed beach towels for a fundraiser. They are selling them for $18

aksik [14]

They need to sell 33, unless you round it up then 34.

3 0

3 years ago

HELP!!!!!!!!!! PLEASE!!!!!!!WILL MARK AS BRAINLIEST

Goshia [24]

<t =33 since triangle RUT is isosceles (RU = TU)

<r + <u + <t = 180 triangle = 180

33 + <u + 33 = 180

66 + <u = 180

< u =114

<rus = < sut from the diagram

<rus + <sut = <u

x + x = 114

2x = 114

divide by 2

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6 0

3 years ago

Read 2 more answers

A bird sees a worm on the ground 50 m. below. The bird dives for the worm at a speed of 6 m/sec. The function h\left( t \right)

iragen [17]

<u>Given</u>:

The height of the bird at time t is given by the function $h(t)=-4.9t^2+6t+50$

We need to determine the time it takes the worm to be eaten by the bird.

<u>Time taken:</u>

The time can be determined by substituting h(t) = 0 in the function.

Thus, we have;

$0=-4.9t^2+6t+50$

Switch sides, we get;

$-4.9t^2+6t+50=0$

Let us solve the equation using the quadratic formula.

Thus, we get;

$t=\frac{-6 \pm \sqrt{6^{2}-4(-4.9) 50}}{2(-4.9)}$

Simplifying, we get;

$t=\frac{-6 \pm \sqrt{36+980}}{-9.8}$

$t=\frac{-6 \pm \sqrt{1016}}{-9.8}$

$t=\frac{-6 \pm 31.87}{-9.8}$

The values of t are given by

$t=\frac{-6 + 31.87}{-9.8}$ and $t=\frac{-6 - 31.87}{-9.8}$

$t=\frac{25.87}{-9.8}$ and $t=\frac{-37.87}{-9.8}$

$t=-2.4$ and $t=3.9$

Since, the value of t cannot be negative, then $t=3.9$

Thus, the time taken by the bird to eat the worm is $t=3.9$ seconds.

Hence, Option B is the correct answer.

5 0

3 years ago

A rectangle has an area of 19.38 cm2. When both the length and width of the rectangle are increased by 1.50 cm, the area of the

Lostsunrise [7]

Answer: $5.7\ cm$

Step-by-step explanation:

Given

Rectangle has an area of $19.38\ cm^2$

Suppose rectangle length and width are $l$ and $w$

If each side is increased by $1.50\ cm$

Area becomes $A_2=35.28\ cm^2$

We can write

$\Rightarrow lw=19.38\quad \ldots(i)\\\\\Rightarrow (l+1.5)(w+1.5)=35.28\\\Rightarrow lw+1.5(l+w)+1.5^2=35.28\\\text{use (i) for}\ lw\\\Rightarrow 19.38+1.5(l+w)=35.28-2.25\\\Rightarrow l+w=9.1\quad \ldots(ii)$

Substitute the value of width from (ii) in equation (i)

$\Rightarrow l(9.1-l)=19.38\\\Rightarrow l^2-9.1l+19.38=0\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{(-9.1)^2-4(1)(19.38)}}{2\times 1}\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{5.29}}{2}\\\\\Rightarrow l=\dfrac{9.1\pm2.3}{2}\\\\\Rightarrow l=3.4,\ 5.7$

Width corresponding to these lengths

$w=5.7,\ 3.4$

Therfore, we can write the length of the longer side is $5.7\ cm$

8 0

3 years ago