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maria [59]
3 years ago
7

A dust particle weighs 7.42 × 10-10 kilograms. What is the weight of 5 × 106 dust particles represented in scientific notation?

Mathematics
2 answers:
Tresset [83]3 years ago
5 0

Answer:

= 3.71 x 10^(-3) kilograms

Step-by-step explanation:

OLEGan [10]3 years ago
3 0
<span>A dust particle weighs 7.42 × 10-10 kilograms. 

Weight of 5 × 106 dust particles = </span>5 × 10^6 x 7.42 x 10^(-10)

= 5 x 7.42 x 10^(6-10)

= 37.1 x 10^(-4)

= 3.71 x 10^(-3) kilograms

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The m∠D is 98° ⇒ answer D

Step-by-step explanation:

* Lets revise some facts in the circle

- The quadrilateral is inscribed in a circle if its four vertices lie on the

  circumference of the circle

- It is called a cyclic quadrilateral

- Every two opposite angles in it are supplementary means the

  sum of their measures is 180°

∵ ABCD is inscribed in a circle

∴ ABCD is a cyclic quadrilateral

∵ ∠A and ∠C are opposite angles in the cyclic quadrilateral ABCD

∴ ∠A and ∠C are supplementary

∴ m∠A + m∠C = 180°

∵ m∠A = 64°

∵ m∠C = (9x - 1)°

∴ 64 + (9x - 1) = 180 ⇒ simplify

∴ 63 + 9x = 180 ⇒ subtract 63 from both sides

∴ 9x = 117 ⇒ divide both sides by 9

∴ x = 13

- Lets find the measure of ∠B

∵ m∠B = (6x + 4)°

∵ x = 13

∴ m∠B = 6(13) + 4 = 78 + 4 = 82°

- Lets find the measure of ∠D

∵ ∠B and ∠D are opposite angles in the cyclic quadrilateral ABCD

∴ ∠B and ∠D are supplementary

∴ m∠B + m∠D = 180°

∵ m∠B = 82°

∴ 82° + m∠D = 180° ⇒ subtract 82° from both sides

∴ m∠D = 98°

* The m∠D is 98°

3 0
4 years ago
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