All categories

2 years ago

A dust particle weighs 7.42 × 10-10 kilograms. What is the weight of 5 × 106 dust particles represented in scientific notation?

Mathematics

2 answers:

Tresset [83]2 years ago

5 0

Answer:

= 3.71 x 10^(-3) kilograms

Step-by-step explanation:

OLEGan [10]2 years ago

3 0

A dust particle weighs 7.42 × 10-10 kilograms.

Weight of 5 × 106 dust particles = 5 × 10^6 x 7.42 x 10^(-10)

= 5 x 7.42 x 10^(6-10)

= 37.1 x 10^(-4)

= 3.71 x 10^(-3) kilograms

You might be interested in

The equation of a parabola is 1/32 (y−2)2=x−1 .

Andru [333]

The given equation of parabola is

$\frac{1}{32} (y-2)^2 = x-1$

Which can also be written as

$x = \frac{1}{32} (y-2)^2 +1$

Here vertex (h,k) is (1,2)

And value of a is

$a = \frac{1}{32}$

Formula of focus is

$(h+ \frac{1}{4a} , k)$

Substituting the values of h,k and a, we will get

$(1+ \frac{1}{4*(1/32) } , 2} = (1+ 8,2) = (9,2)$

Therefore the correct option is the last option .

6 0

2 years ago

Read 2 more answers

5^5=75+30 TRUE OR FALSE p.s. if this gets deleted ama demolish u

agasfer [191]

false is the answer.

7 0

2 years ago

Read 2 more answers

What types of solutions will a quadratic equation have when the discriminant b2 − 4ac in the quadratic formula is a perfect squa

netineya [11]

The discriminant must be zero.

Step-by-step explanation:

A Perfect-Square Trinomial is given by the form:

$(\alpha x \pm \beta)^2=(\alpha^2x^2 \pm 2\alpha x \beta + \beta^2)$

The discriminant in the quadratic formula is:

$\Delta=b^2-4ac \\ \\ \\ Here: \\ \\ a= \alpha^2 \\ \\ b=2\alpha \beta \\ \\ c=\beta^2 \\ \\ \\ So: \\ \\ \Delta=(2\alpha \beta )^2-4(\alpha^2)(\beta^2) \\ \\ \Delta=4\alpha^2 \beta^2-4\alpha^2 \beta^2=0$

So in order to get a perfect square, the discriminant must be zero.

<h2>Learn more:</h2>

Discriminant: brainly.com/question/1537997

#LearnWithBrainly

4 0

2 years ago

If 5x-8w=9, then solve for x, in terms of w and z

babymother [125]

Answer:

Step-by-step explanation:

5x-8w=9 add 8w : 5x-8w+8w = 9+8w

5x = 9+8w

now divid by 5 : x = (9+8w)/5

7 0

2 years ago

Read 2 more answers

The legth of a rectangle is 15 inches less then twice its width, w. If the perimeter of the rectangle is 96 inches what is the l

KATRIN_1 [288]

Answer:

length of the rectangle=27"

Step-by-step explanation:

length be = l; width be = b

2b-15= l

perimeter= 2(l+b)

=2(2b-15+b)=96

=2(3b-15) =96

3b-15 .=48

3b=48+15=63

b=21. Therefore l = (2 x 21) - 15=42-15 =27"

8 0

2 years ago