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exis [7]
3 years ago
13

HELP!! Im not sure what i did wrong!!

Mathematics
1 answer:
Igoryamba3 years ago
7 0

I'm not sure what exactly you did wrong, but I agree with you that the sample size is too small, so the correct answer will probably be the fourth options. Hope that this gives you some confidence, and 'm sorry not to be able to help you any further...

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16.4.57 Question Help A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill You bl
Rudiy27

Answer:

$ 7.7

Step-by-step explanation:

Given,

There are 18 $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill,

Total number of bills = 18 + 10 + 8 + 3 + 1 = 40,

\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Thus,

The probability of $ 1 = \frac{18}{40}

The probability of $ 5 = \frac{10}{40}

The probability of $ 10 = \frac{8}{40}

The probability of $ 20 = \frac{3}{40}

The probability of $ 100 = \frac{1}{40}

If a bill is selected randomly,

The expected value of the bill

=\frac{18}{40}\times 1+\frac{10}{40}\times 5+\frac{8}{40}\times 10+\frac{3}{40}\times 20+\frac{1}{40}\times 100

=\frac{18+50+80+60+100}{40}

=\frac{308}{40}

= $ 7.7

5 0
3 years ago
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