Z
Z=kX
When x=6, z=18,
Finding value of z,
18=k*6
k=3
Z=3X
when x=10,
Z=3*10
Z=30
Part B;
Z
z=
Where x is a constant of proportionality,
when x=3, z=2
2=
a=3*2
a=6
When x is 13,
Z=
I think its D and A
A. A and B
B. A and D
C. B and C
D. B and D
Answer:
-8 and 3
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
