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natima [27]
3 years ago
12

Pls help meeeeeeee with this

Mathematics
1 answer:
hammer [34]3 years ago
4 0
:):(:(:):)(:(:$:):(:(:(:):)3():):);;
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2ci 1=-d 6-ci solve for c and d
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Imaginary numbers ? just equate the imaginary with imaginary and real with real

<span>2ci 1=-d 6-ci <<< what the * is that ?

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1/6 (12t -18)<br> ANSWER ASAP
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Suppose a family has three children of different ages. We assume that all combinations of boys and girls are equally likely. (a)
Ivan

Answer:

a) There are 8 possible combinations and each probability is 1/8.

b) The probability that it is a boy given that there are two girls is 3/8

Step-by-step explanation:

a) The sample space is given by:

BBB (3 boys)

BBG (Boy, boy, girl)

BGB (Boy, girl, boy)

BGG (Boy, girl, girl)

GBB (girl, boy, boy)

GBG (girl, boy, girl)

GGB (girl, girl, boy)

GGG (3 girls)

The probability of each combination is the same:

P(BBB)=P(B∩B∩B)=\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{1}{8}

2) There are three possible combinations in which there are 2 girls and 1 boy:

BGG, GBG, GGB

So the probability is given by:

P(BGG ∪ GBG ∪ GGB)=\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{3}{8}

6 0
3 years ago
B. Name all three angles<br> listed in the figure below:<br> C. Solve for X
muminat
The angles are wer . rek . wek
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3 years ago
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