2 years ago

Pls help meeeeeeee with this

Mathematics

1 answer:

hammer [34]2 years ago

4 0

:):(:(:):)(:(:$:):(:(:(:):)3():):);;

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If a 12-student class averaged 90 on a test, and a 20-student class averaged 80 on the test, then all 32 students averaged

Alexxx [7]

Let the marks of the students in class 1 be

$m_1, m_2, ....., m_1_2$

the average of these 12 marks is 90, so

$\frac{m_1+ m_2+ .....+ m_1_2}{12}=90$

which means

$m_1+ m_2+ .....+ m_1_2=90*12=1080$

similarly, let $n_1, n_2, ....., n_2_0$ be the marks of the students in the second class,

so $\frac{n_1+ n_2+ ..... n_2_0}{20}=80$

which means $n_1+ n_2+ ..... n_2_0=80*20=1600$

The 32 students averaged:

$\frac{(m_1+ m_2+ .....+ m_1_2)+(n_1+ n_2+ ..... n_2_0)}{12+20}= \frac{1080+1600}{32}= \frac{2680}{32}= 83.75$

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DanielleElmas [232]

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Step-by-step explanation:

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52(7)^1/5<br><br> Need help solving this problem. I don’t have Ti-84 Calculator yet

frozen [14]

Answer:

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Step-by-step explanation:

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pashok25 [27]

That is around 13 or 14 cents. The specific answer is 13.65853659 cents, but you can either round up to 14 or round down to 13 (rounding up to 14 is the correct way to do it.)

First you divide 1.12 by 8.2 to get the unit rate because It takes $1.12 to buy 8.2 ounces. 1.12/8.2=13.65853659

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liubo4ka [24]

Answer:

No .1

Ans ; 2

No.2

Ans ; 3

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Multiply or add and if the value is whole no. then its W else L

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