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wolverine [178]
3 years ago
10

What is another way to write the equation 7/8x × 3/4 = -6?

Mathematics
2 answers:
____ [38]3 years ago
8 0
Its option C btw i got help from my tutor with this yesterday
Vesnalui [34]3 years ago
6 0
The correct answer is A) 7 (x/8) + 3/4 = -6 
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Andru [333]

\alpha  \:  \: (0 \infty )
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4 0
3 years ago
Divide the following
Brrunno [24]
Good morning

(-6m^7 + 20m^6) / 2m^4
= (-6m^3 + 20m^2) / 2
Now just divide them
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4 0
4 years ago
In an examination, 40% of students passed in Maths only, 30% passed in Science only and 10% students failed in both subjects. If
Nikitich [7]

Answer:

  • 400 students

Step-by-step explanation:

<u>Given:</u>

  • 40% of students passed in Maths only
  • 30% passed in Science only
  • 10% students failed in both subjects
  • 200 students passed in science

Let the total number of students is x.

<u>Then the number of students passed in both subjects is:</u>

  • x - (0.4x + 0.3x + 0.1x) =
  • x - 0.8x =
  • 0.2x

<u>Number of students passed in science is:</u>

  • 0.3x + 0.2x = 200
  • 0.5x = 200
  • x = 200/0.5
  • x = 400

Venn diagram looks like below.

<u>Consider 'Math' and 'Science' as two circles, 'Both' is the intersection of circles, 'Neither' is outside of the two circles.</u>

  • Math         Both          Science            Neither
  • 40%          20%             30%                  10%
7 0
3 years ago
Suppose that Motorola uses the normal distribution to determine the probability of defects and the number of defects in a partic
Mekhanik [1.2K]

Answer:

\mathbf{P(X < 9.85 \ or \ X> 10.15) \approx 0.3171}     to four decimal places.

\mathbf{P(X < 9.85 \ or \ X> 10.15) =0.0027}  to four decimal places.

Step-by-step explanation:

a)

Assuming X to be the random variable which replace the amount of defectives and follows standard normal distribution whose mean  (μ) is 10 ounces and standard deviation (σ) is 0.15

The values of the random variable differ from mean  by ±  1 \such that the values are either greater than (10+ 0.15) or less than  (10-0.15)

= 10.15 or  9.85.

The  probability that the amount of defectives which are either greater than 10.15 or less than 9.85 can be calculated as follows:

P(X < 9.85 \ or \ X> 10.15) = 1-P ( \dfrac{9.85-10}{0.15}< \dfrac{X-10}{0.15}< \dfrac{10.15-10}{0.15})

P(X < 9.85 \ or \ X> 10.15) = 1- \phi (1) - \phi (-1)

Using the Excel Formula ( = NORMDIST (1) ) to calculate for the value of z =1 and -1 ;we have: 0.841345 and 0.158655 respectively

P(X < 9.85 \ or \ X> 10.15) = 1- (0.841345-0.158655)

P(X < 9.85 \ or \ X> 10.15) =0.31731

\mathbf{P(X < 9.85 \ or \ X> 10.15) \approx 0.3171}     to four decimal places.

b) Through process design improvements, the process standard deviation can be reduced to 0.05.

The  probability that the amount of defectives which are either greater than 10.15 or less than 9.85 can be calculated as follows:

P(X < 9.85 \ or \ X> 10.15) = 1-P ( \dfrac{9.85-10}{0.05}< \dfrac{X-10}{0.05}< \dfrac{10.15-10}{0.05})

P(X < 9.85 \ or \ X> 10.15) = 1- \phi (3) - \phi (-3)

Using the Excel Formula ( = NORMDIST (3) ) to calculate for the value of z =3 and -3 ;we have: 0.99865 and 0.00135 respectively

P(X < 9.85 \ or \ X> 10.15) = 1- (0.99865-0.00135)

\mathbf{P(X < 9.85 \ or \ X> 10.15) =0.0027}  to four decimal places.

(c)  What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean?

The main advantage of reducing the process variation is that the chance of getting the defecting item will be reduced as we can see from the reduction which takes place from a to b from above.

7 0
4 years ago
I REALLY NEED YOUR HELP DUE AT THE END OF CLASS.
shutvik [7]

Answer:

Type 2

Step-by-step explanation:

Equation of the line is:

y=2

slope is 0

4 0
3 years ago
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