All categories

4 years ago

Given: f(x)=-2x+2 and g(x)=4x+8 which table set up is correct to solve the equation f(x)=g(x)

Mathematics

1 answer:

sertanlavr [38]4 years ago

3 0

<h3>The solution to f(x) = g(x) is x = -1</h3>

<em><u>Solution:</u></em>

Given that,

f(x) = - 2x + 2

g(x) = 4x + 8

Solve the equation f(x) = g(x)

-2x + 2 = 4x + 8

Combine the like terms

Keep the variable "x" terms in one side and move constants to other side

4x + 2x = 2 - 8

6x = -6

Divide both sides by 6

x = -1

Thus solution to f(x) = g(x) is x = -1

You might be interested in

Select the best real-world situation that can be represented by 15 + c = 19.50. Then solve the equation and describe what your a

Misha Larkins [42]

Answer:

Step-by-step explanation:

15+c=19.50

c=19.50-15

=4.5

6 0

3 years ago

Read 2 more answers

Plssssssss do 1, 2, 3, 4, and 5

Delicious77 [7]

Answer/Explanation:

3 · 7 + (3 · 8n
21 + 24n

8 · 2x + 8 · 7
16x + 56

-4 · 7r + (-4) · 7
-28r + (-28)
-28r -28

-2 · n - 2 · (-9)
-2n + 18

-6 + 9 · 8 + 9 · (-2b)
-6 + 72 - 18b
66 - 18b

7 0

3 years ago

Not sure f either of my answers would satisfy the question in the second picture

xz_007 [3.2K]

$\bf \begin{array}{llll}
tan(\alpha)=-\cfrac{80}{15}\qquad II\\\\
x=-15\\
y=8\\
r=17
\end{array} \qquad \qquad 
\begin{array}{llll}
cos(\beta)=\cfrac{5}{6}\qquad I\\\\
x=5\\
y=\sqrt{11}\\
r=6
\end{array}\\\\
-----------------------------\\\\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\\\\\
sin({{ \alpha}} + {{ \beta}})=\cfrac{8}{17}\cdot \cfrac{5}{6}+\cfrac{-15}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{40-15\sqrt{11}}{102}$

$\bf cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})
\\\\\\
\cfrac{-15}{17}\cdot \cfrac{5}{6}-\cfrac{8}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{-75-8\sqrt{11}}{102}$

$\bf tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}
\\\\\\
tan({{ \alpha}} + {{ \beta}}) = \cfrac{-\frac{8}{15}+\frac{\sqrt{11}}{5}}{1-\left( -\frac{8}{15}\cdot \frac{\sqrt{11}}{5} \right)}\implies 
\cfrac{\frac{-8+3\sqrt{11}}{15}}{1+\frac{8\sqrt{11}}{75}}
\\\\\\
tan({{ \alpha}} + {{ \beta}}) =\cfrac{\frac{-8+3\sqrt{11}}{15}}{\frac{75+8\sqrt{11}}{75}}\implies \cfrac{-8+3\sqrt{11}}{15}\cdot \cfrac{75}{75+8\sqrt{11}}
\\\\\\
$

$\bf tan({{ \alpha}} + {{ \beta}}) =\cfrac{-8+3\sqrt{11}}{1}\cdot \cfrac{3}{75+8\sqrt{11}}\implies \cfrac{15\sqrt{11}-40}{75+8\sqrt{11}}$

6 0

4 years ago

What is 3/8 multiplied by 6

zalisa [80]

In multiplying fractions, you don't need a common denominator.

3/8 * 6/1 = 18/8
I multiplied the numerator by the other numerator and multiplied the denominator by the other denominator

Now we have to simplify 18/8, the number 2 can go into both numbers

9/4 is the final answer.

7 0

3 years ago

Write all prime numbers between 20 and 40

ivann1987 [24]

Prime number between 20 and 40:

23 29 31 37

4 0

3 years ago