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gregori [183]
3 years ago
13

alex bought 2 dvd's for $28 each. and a dvd player for $85. He gave the cashier $150.00 how much change should alex heve receive

d from the cashier.?​
Mathematics
1 answer:
liraira [26]3 years ago
8 0
The answer is $9

28+28+85=141

150-141=$9

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The slope for A is 2/5 and the slope for B is -2/6
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3 years ago
A dish tv satellite dish is the shape of a paraboloid. the dish is 36 inches wide, and 8 inches deep. how many inches should the
MrRa [10]
Refer to the diagram shown below. It shows a vertical cross-section of the paraboloid through its axis of symmetry.

Let the vertex of the parabola be at the origin. Then its equation is of the form
y = bx²

Because the parabola passes through (18,8), therefore
8 = b(18²)
b = 0.02469
The parabola is y = 0.02469x².

The receiver should be placed at the focal point of the paraboloid for optimal reception.
The y-coordinate of the focus is
a = 1/(4b) = 1/0.098765 = 10.125 in

Answer: The receiver is located at 10.125 inches from the vertex.

4 0
3 years ago
Please , I didn't have time to study. god bless to all <3
Naily [24]
This is the first half of the question.
Let's solve your equation step-by-step.5x=9x3+2x2−5x+4Step 1: Subtract 9x^3+2x^2-5x+4 from both sides.5x−(9x3+2x2−5x+4)=9x3+2x2−5x+4−(9x3+2x2−5x+4)−9x3−2x2+10x−4=0Step 2: Use cubic formula.x=−1.31953Answer:<span>x=<span>−1.31953


</span></span>
3 0
3 years ago
What is 0.3,0.13,0.19 and 0.31 in order from least to greatest
wariber [46]
0.3 then 0.13 then 0.19 then 0.31
have a nice day ;)
3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20If%20%7D%20%5Cint_%7B%5Cfrac%7B-1%7D%7B%5C
Elodia [21]

We want to evaluate

\displaystyle \int_{-\frac1{\sqrt2}}^{\frac1{\sqrt2}} \sqrt{\left(\frac{x-1}{x+1}\right)^2 + \left(\frac{x+1}{x-1}\right)^2 - 2} \, dx

First we note that the integrand is even (replacing x with -x doesn't fundamentally alter the function being integrated), so this is equal to

\displaystyle 2 \int_0^{\frac1{\sqrt2}} \sqrt{\left(\frac{x-1}{x+1}\right)^2 + \left(\frac{x+1}{x-1}\right)^2 - 2} \, dx

The radicand reduces significantly to

\displaystyle \left(\frac{x-1}{x+1}\right)^2 + \left(\frac{x+1}{x-1}\right)^2 - 2 = \frac{16x^2}{(1-x^2)^2}

so that taking the square root, we simplify the integral to

\displaystyle 8 \int_0^{\frac1{\sqrt2}} \frac x{1-x^2} \, dx

which is trivially computed with a substitution of y = 1 - x^2 and dy=-2x\,dx:

\displaystyle -4 \int_1^{\frac12} \frac{dy}y = 4 \int_{\frac12}^1 \frac{dy}y = -4 \ln\left(\frac12\right) = \ln(2^4) = \boxed{\ln(16)}

7 0
2 years ago
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