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<u>RATIO</u></h2>
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» There are 8 watermelons and 6 apples in the shopping cart. What is the ratio of apples to total fruits? Be sure to write your answer in lowest terms.
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Based on the problem, there are 8 watermelons and 6 apples in the shopping cart. So,
Therefore, the ratio of apples to total fruits is 8:14 and its lowest term is 4:7.
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What we know:
we know that there are <u>75</u> chicks in the hen house, we also know that in all there are 108 chicks
What we need to find:
we need to find out how many chicks were outside
Answer equation:
108 - 75 = 33
The equivalent answer to this expression is found by using the distributive property.
(-2a - 12)
Simply multiply the negative 2 into the second parenthesis.
Answer:
Price of each phone: 
Price of each accessory: 
Step-by-step explanation:
Let be "p" the price in dollars of each phone and "a" the price in dollars of each accessory.
Set up a system of equations:

You can use the Elimination Method to solve the system.
Multiply the second equation by -2 and add both equations:

Substitute the value of "a" into the first equation and solve for "p":

Answer: the general formula for the total surface area of a regular pyramid isbT. S. A. =12pl+B where p represents the perimeter of the base