Question

WILL GIVE BRAINLIEST

Answer 1

For this case we have by definition, that the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We need two points through which the line passes to find the slope:

$(0, -2)\\(-3,0)$

We found the slope:

$m = \frac {y2-y1} {x2-x1}\\m = \frac {0 - (- 2)} {- 3-0} = \frac {2} {- 3} = - \frac {2} {3}$

So, the equation is of the form:

$y = - \frac {2} {3} x + b$

We substitute a point to find "b":

$-2 = - \frac {2} {3} (0) + b\\-2 = b$

Finally, the equation is:

$y = - \frac {2} {3} x-2$

Answer:

Option C