A=43°
B=82°
c=28
1) A+B+C=180°
Replacing A=43° and B=82° in the equation above:
43°+82°+C=180°
125°+C=180°
Solving for C. Subtracting 125° both sides of the equation:
125°+C-125°=180°-125°
C=55° (option B or C)
2) Law of sines
a/sin A=b/sin B=c/sin C
Replacing A=43°, B=82°, C=55°, and c=28 in the equation above:
a/sin 43°=b/sin 82°=28/sin 55°
2.1) a/sin 43°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 43°:
sin 43°(a/sin 43°)=sin 43°(28/sin 55°)
a=28 sin 43° / sin 55°
Using the calculator: sin 43°=0.681998360, sin 55°=0.819152044
a=28(0.681998360)/0.819152044
a=23.31185549
Rounded to one decimal place
a=23.3
2.2) b/sin 82°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 82°:
sin 82°(b/sin 82°)=sin 82°(28/sin 55°)
b=28 sin 82° / sin 55°
Using the calculator: sin 82°=0.990268069, sin 55°=0.819152044
b=28(0.990268069)/0.819152044
b=33.84903466
Rounded to one decimal place
b=33.8
Answer: Option B) C=55°, b=33.8, a=23.3
Answer:
-4 would be the answer i think!
Step-by-step explanation:
8/12 and 4/6 and10/15 and20/30 and 40/60
Ah yes, good ol’ Pythagorean’s theorem.
The hypotenuse is the opposite of the 90 degree angle, the longest side of the triangle.
The legs are opposite of the acute angles
Formula: a^2 + b^2 = c^2
2:
Let’s plug in some values
(6)^2 + (3)^2 = c^2
C = 6.7
The side will be 6.7 units
3)
Let’s plug in some values
(13.3)^2 = (9.7)^2 + (b)^2
(13.3)^2 - (9.7)^2 = b^2
176.89 - 94.09 = b^2
b = 9.1
The side will be 9.1 units
Oi :)
1) There are 3 significant digits
2)
15 Mi/h = 22 ft/s
3)
4)
There are 4 significant digitis. Leter C
