Question

9x^2 + 24x + 20 = 4 Solve this by factoring. Thank you!

Answer 1

Note that,

$9x^2+24x+20=4\Longrightarrow9x^2+24x+16$

Which factors to,

$(3x+4)^2=0\Longrightarrow3x+4=0$

And simplifies to solution C,

$\boxed{x=-\dfrac{4}{3}}$

Hope this helps.

Any additional questions please feel free to ask.

r3t40

Answer 2

Answer:

$\large\boxed{C.\ x=-\dfrac{4}{3}}$

Step-by-step explanation:

$9x^2+24x+20=4\qquad\text{subtract 4 from both sides}\\\\9x^2+12x+12x+16=0\\\\3x(3x+4)+4(3x+4)=0\\\\(3x+4)(3x+4)=0\\\\(3x+4)^2=0\iff3x+4=0\qquad\text{subtract 4 from both sides}\\\\3x=-4\qquad\text{divide both sides by 3}\\\\x=-\dfrac{4}{3}$