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Eva8 [605]
3 years ago
15

Which equation shows that the Pythagorean identity is true for 0 = 180°?

Mathematics
2 answers:
bogdanovich [222]3 years ago
5 0

Answer:

For theta=360°

0^2+1^2=1

Step-by-step explanation:

A P E X

THANK ME LATER :)

Romashka-Z-Leto [24]3 years ago
3 0
Option C is correct.
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3 years ago
Find a formula for a function that has vertical asymptotes x = 2 and x = 7 and horizontal asymptote y = 2.
Pie
Hello : 

 

hello : <span>
1 ) if : x</span>ـــــــ> ± ∞  <span>
 limf(x)   = b     ....(b</span>∈R)     so : y=b is the equation of the line horizontal asymptote.

<span>
2) if : x</span>ـــــــ> a ...(a∈R)<span>
 limf(x)   = ± ∞  
<span>so : x=a is the equation of the line vertical asymptote.</span></span>

<span><span>hint : in this exercice : a = 2 or a = 7  but : b=2</span></span>

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3 years ago
What is the area of this figure?
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59.5 cm2 is the answer.
7 0
3 years ago
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If f(x) = 1/2x^2 - (1/4x +3), what is the value of<br> f(8)?
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Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
5 points
jonny [76]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{2}x-5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 2 and passes through (4 , -3)

(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y+3=2x-8\implies y=2x-11

5 0
2 years ago
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