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d1i1m1o1n [39]
2 years ago
5

Please help me! ASAP!

Mathematics
1 answer:
Alinara [238K]2 years ago
6 0
Subtract the cost of dog food with your total amount and then find the percentage of that amount based on the total you have so in this case it would be 85 / 1695 * 100 and then you will get your percentage
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Priyanti ate 150 raisins in five days. If she ate 7 more raisins each day than she did the previous day, how many raisins did sh
marta [7]

Answer:

this means she ate an average of 30 raisins each day

so she ate 30 on the third day

so the amount she ate each day is like this

1. 16

2. 23

3. 30

4. 37

5. 44

16 + 23 +30 +37 +44=150

8 0
2 years ago
Read 2 more answers
Can someone please help me with question 4
bazaltina [42]
Yes what is the four question
4 0
3 years ago
When actual trials are difficult to conduct, you can find experimental probabilities using this model of one or more events.
r-ruslan [8.4K]
Two events are mutually exclusive if they cannot occur in the same trial of an experiment.
6 0
2 years ago
What is the nth term rule of the linear sequence below?
hoa [83]

Answer:

a_n=-5-2(n-1)

Step-by-step explanation:

Since this sequence starts with -5 and decreases by 2 with each term, its rule would be:

a_n=-5-2(n-1)

Hope this helps!

7 0
3 years ago
Sarah has 284 coins in a piggy bank with a total value of $22.78. Sarah has 173 pennies, 5 more dimes than nickels, the rest are
pickupchik [31]
Let P = number of coins of pennies (1 penny = 1 cent)
Let N = number of coins of nickels (1 nickel = 5 cents)
Let D = number of coins of dimes (1 dime = 10 cents)
Let Q = number of coins of quarters (1 quarter = 25 cents)

a) P + N + D + Q = 284 coins, but P = 173 coins, then:
173 + N + D + Q =284 coins
(1)  N + D + Q = 111 coins

b) D = N + 5 OR D - N =5 coins
(2) D - N = 5 coins

c) Let's find the VALUE in CENTS of (1) that is N + D + Q = 111 coins
5N + 10D + 25 Q = 2,278 - 173 (1 PENNY)
(3) 5N + 10D + 25Q = 2105 cents
Now we have 3 equation with 3 variables:

(1)  N + D + Q = 111 coins
(2) D - N = 5 coins
(3) 5N + 10D + 25Q = 2105 cents
Solving it gives:
17 coins N ( x 5 = 85 cents)
22 coins D ( x 10 = 220 cents)
72 coins D ( x 25 = 1,800 cents)
and 173 P,
proof:
that makes a total of 85+2201800+172 =2,278 c or $22.78




7 0
3 years ago
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