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lakkis [162]
3 years ago
7

Find the x- and y-intercepts of the following line: 4x − 3y = 12

Mathematics
1 answer:
Slav-nsk [51]3 years ago
3 0

Answer:

x-intercept: (3,0)

y-intercept: (0,-4)

Step-by-step explanation:

To find the x and y-intercepts, we first need to understand what they are. X and y-intercepts are points on the line that passes through the x-axis and y-axis. When a point is an x-intercept, it passes through the x-axis. This means the x-coordinate is an integer, while the y-coordinate is always 0. This can be denoted by (x,0). When a point is a y-intercept, it passes through the y-axis. This means the y-coordinate is an integer, while the x-coordinate is always 0. This can be denoted by (0,y).

Now that we know what x and y-intercepts are, we can plug in x=0 and y=0 to find the intercepts.

x-intercept

4x-3y=12            [plug in y=0]

4x-3(0)=12          [multiply]

4x-0=12              [add both sides by 0]

4x=12                 [divide both sides by 4]

x=3

---------------------------------------------------------------------------------------------------------

y-intercept

4x-3y=12            [plug in x=0]

4(0)-3y=12         [multiply]

0-3y=12             [subtract both sides by 0]

-3y=12               [divide both sides by -3]

y=-4

Therefore, the x-intercept is (3,0) and y-intercept is (0,-4).

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Part A
masya89 [10]

Answer:

Part A) The area of triangle i is 3\ cm^{2}

Part B) The total area of triangles i and ii is 6\ cm^{2}

Part C) The area of rectangle i is 20\ cm^{2}

Part D) The area of rectangle ii is 32\ cm^{2}

Part E) The total area of rectangles i and iii is 40\ cm^{2}

Part F) The total area of all the rectangles is 72\ cm^{2}

Part G) To find the surface area of the prism, we need to know only the area of triangle i and the area of rectangle i and the area of rectangle ii, because the area of triangle ii is equal to the area of triangle i and the area of rectangle iii is equal to the area of rectangle i

Part H) The surface area of the prism is 78\ cm^{2}

Part I) The statement is false

Part J) The statement is true

Step-by-step explanation:

Part A) What is the area of triangle i?

we know that

The area of a triangle is equal to

A=\frac{1}{2} (b)(h)

we have

b=4\ cm

h=1.5\ cm

substitute

A=\frac{1}{2} (4)(1.5)

Ai=3\ cm^{2}

Part B) Triangles i and ii are congruent (of the same size and shape). What is the total area of triangles i and ii?

we know that

If Triangles i and ii are congruent

then

Their areas are equal

so

Aii=Ai

The area of triangle ii is equal to

Aii=3\ cm^{2}

The total area of triangles i and ii is equal to

A=Ai+Aii

substitute the values

A=3+3=6\ cm^{2}

Part C) What is the area of rectangle i?

we know that

The area of a rectangle is equal to

A=(b)(h)

we have

b=2.5\ cm

h=8\ cm

substitute

Ai=(2.5)(8)

Ai=20\ cm^{2}

Part D) What is the area of rectangle ii?

we know that

The area of a rectangle is equal to

A=(b)(h)

we have

b=4\ cm

h=8\ cm

substitute

Aii=(4)(8)

Aii=32\ cm^{2}

Part E) Rectangles i and iii have the same size and shape. What is the total area of rectangles i and iii?

we know that

Rectangles i and iii are congruent (have the same size and shape)

If rectangles i and iii are congruent

then

Their areas are equal

so

Aiii=Ai

The area of rectangle iii is equal to

Aiii=20\ cm^{2}

The total area of rectangles i and iii is equal to

A=Ai+Aiii

substitute the values

A=20+20=40\ cm^{2}

Part F) What is the total area of all the rectangles?

we know that

The total area of all the rectangles is

At=Ai+Aii+Aiii

substitute the values

At=20+32+20=72\ cm^{2}

Part G) What areas do you need to know to find the surface area of the prism?

To find the surface area of the prism, we need to know only the area of triangle i and the area of rectangle i and the area of rectangle ii, because the area of triangle ii is equal to the area of triangle i and the area of rectangle iii is equal to the area of rectangle i

Part H) What is the surface area of the prism? Show your calculation

we know that

The surface area of the prism is equal to the area of all the faces of the prism

so

The surface area of the prism is two times the area of triangle i plus two times the area of rectangle i plus the area of rectangle ii

SA=2(3)+2(20)+32=78\ cm^{2}

Part I) Read this statement: “If you multiply the area of one rectangle in the figure by 3, you’ll get the total area of the rectangles.” Is this statement true or false? Why?

The statement is false

Because, the three rectangles are not congruent

The total area of the rectangles is 72\ cm^{2} and if you multiply the area of one rectangle by 3 you will get 20*3=60\ cm^{2}

72\ cm^{2}\neq 60\ cm^{2}

Part J) Read this statement: “If you multiply the area of one triangle in the figure by 2, you’ll get the total area of the triangles.” Is this statement true or false? Why?

The statement is true

Because, the triangles are congruent

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Answer:

The probability that he has exactly 2 hits in his next 7 at-bats is 0.3115.

Step-by-step explanation:

We are given that a baseball player has a batting average of 0.25 and we have to find the probability that he has exactly 2 hits in his next 7 at-bats.

Let X = <u><em>Number of hits made by a baseball player</em></u>

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r}; x = 0,1,2,......

where, n = number of trials (samples) taken = 7 at-bats

            r = number of success = exactly 2 hits

            p = probability of success which in our question is batting average

                   of a baseball player, i.e; p = 0.25

SO, X ~ Binom(n = 7, p = 0.25)

Now, the probability that he has exactly 2 hits in his next 7 at-bats is given by = P(X = 2)

          P(X = 2) =  \binom{7}{2}\times 0.25^{2} \times (1-0.25)^{7-2}

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                        =  <u>0.3115</u>

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A particular psychological test is used to measure need for achievement. The average test score for all university students in O
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Answer:

Only B and C are always true.

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Sample Mean = 110 (given)

Margin of Error = (Critical value) × (Standard deviation of the distribution of sample means)

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The critical value usually varies at different confidence levels and degree of freedoms.

The higher the confidence level, the higher the critical value and the higher the margin of error leading to a wider range.

Hence, a confidence interval of 95% will have a higher critical value than a confidence interval of 90%. Hence, statement C is proved once that 'for n = 100, the 95% confidence interval will be wider than the 90% confidence interval'.

After obtaining the critical value, we then obtain the standard deviation of the distribution of sample means or simply the standard error of the mean. This is given as

σₓ = σ/√n

where σ = standard deviation; which isn't given. The standard deviation might be high enough to guarantee that the Margin of error is high too for the confidence interval to contain 115 or low enough to ensure that the Margin of error is very small and the confidence interval will not contain 115.

Or the sample size might be high enough to make the standard error of the mean to be eventually small and lead to a small margin of error and the condidence interval will not contain 115.

The point is, it isn't always sure that the resulting interval.would contain 115. So, statement A isn't always true.

Then from σₓ = σ/√n,

n = sample size, a large sample size means a more narrow confidence interval and a small sample size means a wider sample size. This proves statement C.

The 95% confidence interval for n = 100 will be more narrow than the 95% confidence interval for n = 50.

Hence, Only B and C are always true.

Hope this Helps!!!

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3 years ago
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