Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
Answer:
6.32455532i
Step-by-step explanation:
Use the square root calculator too find it
I’m okay stressed out cuz homework haha
Answer:
11 quarters
Step-by-step explanation:
First, I subtract : 3.45 - .70 = 2.75
Then, divide : 2.75 by 25 ( a quarter ) = .11
Check : 11 x 25 = 2.75 -------------> 2.75 + .70 = 3.45
Hope this helps :)
It's D because 2 it's not a parallelogram and 4 is a parallelogram
