Alright, since there are 5 numbers, and the mean (or average) is (sum)/(amount of numbers), we have (sum)/5=14. Multiplying both sides by 5, we have the sum being 80. The median of 10 means that in a, b, c, d, e, 10 has to be c and the numbers have to be in ascending order. A and b must be 10 or lower, while d and e must be 10 or higher. Putting some random numbers in, we can have 1, 1, 10, 15, and e. We left e there because the sum needs to be 80, and since 1+1+10+15=27, 80-27=53=e. This, however, would not work if e was less than 10 and we therefore would have needed to make some numbers lower to compensate for this. Our answer is therefore 1, 1, 10, 15, 53
Answer:
its blurry for me sorry
Step-by-step explanation:
The perimeters of both are equal.
The side of the square is 12.
Therefore, its area equals to : 12² = 144
The rectangle base is 19.
Because it has the same perimeter as the square's, so rectangle perimeter is : 19 + 19 + side + side = 12 + 12 + 12 + 12
= 38 + 2side = 48
= 2side = 48 - 38
= side of rectangle = 5
Therefore, its area is 19 x 5 = 95
If you subtract it from the area of the square, you will get : 144 - 95 = 49.
So the answer is : the area of the square is 49 units largee than the area of the square (C)
