Given:
x, y and z are integers.
To prove:
If
is even, then at least one of x, y or z is even.
Solution:
We know that,
Product of two odd integers is always odd. ...(i)
Difference of two odd integers is always even. ...(ii)
Sum of an even integer and an odd integer is odd. ...(iii)
Let as assume x, y and z all are odd, then
is even.
is always odd. [Using (i)]
is always odd. [Using (i)]
is always even. [Using (ii)]
is always odd. [Using (iii)]
is always odd.
So, out assumption is incorrect.
Thus, at least one of x, y or z is even.
Hence proved.
Answer:
5/4f i think
Step-by-step explanation:
Equality d is true, the others aren't.
Answer: 83,662,774
Step-by-step explanation:
3 to 5 feet is the ratio in lowest form