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agasfer [191]
2 years ago
5

How to simplify -7 + 3 - 20

Mathematics
2 answers:
PtichkaEL [24]2 years ago
5 0

Answer:

-24

Step-by-step explanation:

-7 +3 is -4

-4+-20 is -24

crimeas [40]2 years ago
5 0

-7 + 3 - 20

= -4 - 20

= -4 + -20

= -24

______

Hope it helps ⚜

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A new car is available with standard or automatic transmission, two or four doors, and it is available in 10 exterior colors. Wh
dezoksy [38]

Answer:

<em>40</em>

Step-by-step explanation:

Given that:

Number of options available for transmission = 2 (Standard or Automatic)

Number of options for doors = 2 (2 doors or 4 doors)

Number of exterior colors available = 10

To find:

Total number of outcomes = ?

Solution:

First of all, let us calculate the number of outcomes for the transmission mode and number of doors options.

1. Standard - 2 doors

2. Standard - 4 doors

3. Automatic - 2 doors

4. Automatic - 4 doors

Number of outcomes possible = 4 (which is equal to number of transmission mode available multiplied by number of doors options i.e. 2\times 2)

Now, these 4 will be mapped with 10 different exterior colors.

Therefore total number of outcomes possible :

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3 years ago
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Sarah drank 75% of a one pint carton of milk at lunchtime. How many ounces of milk were left in the carton? PLZZ help! Will mark
Taya2010 [7]
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Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

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P = 1-0.9243 = 0.0757

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Any answer less than one would work, soothe answers are A and D
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