Set up an en equation and use it to solve for x
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let h represent the hypotenuse, then
h² = 5² + ( )² = 25 + 2 = 27 ( take the square root of both sides )
h = ← exact value