Which situation can be represented by the equation -4× 5= -20?

Aisha collects 1p coins and 2p coins. 24 of these are 1p coins. The probability of choosing a 2p coin at random is 1/2 How much

sdas [7]

Answer:

Aisha has 24 2p coins and 24 1p coins, then she has in total:

2p*(24) + 1*p*(24) = 48p + 24p = 72p

Step-by-step explanation:

Suppose that we have a set of N elements in a bag (if the bag is closed and we put our hand inside to grab one element, we could not distinguish them apart), and K of these elements have a given property (for example, these are red).

The probability of selecting at random one of these red elements is equal to the quotient between the number of elements with that property (K) and the total number of elements in the bag (N)

P = K/N

Now let's go to our problem.

We have 24 1p coins.

We have X 2p coins.

Then the total number of coins is: (24 + X)

We know that the probability of choosing at random a 2p coin is then:

P = X/(24 + X)

And we know that this is equal to 1/2

Then:

X/(24 + X) = 1/2

X = (1/2)*(24 + X) = 24/2 + X/2

X = 12 + X/2

X - X/2 = 12

X/2 = 12

X = 2*12 = 24

Then Aisha has 24 2p coins.

Aisha has 24 2p coins and 24 1p coins, then she has in total:

2p*(24) + 1*p*(24) = 48p + 24p = 72p

7 0

3 years ago

Help with math? Thanks in advance.

erastovalidia [21]

A. Add up to 180 degrees. Hope this helps.

7 0

3 years ago

Read 2 more answers

In physics, pressure is the amount of force exerted on a surface per unit area, P=F/A .The pressure, in atmospheres (atms), of a

xz_007 [3.2K]

Answer:

{r|r>0}

Step-by-step explanation:

Pressure is the amount of force exerted on a surface per unit area, P=F/A.

The pressure, in atmospheres (atms), of a liquid on the circular base of a bucket is represented by the composite function PoA(r), where P(A) = 375 / A and A (r) = pi r²

We know that the domain is the set of input values.

Pressure, $P=\dfrac{F}{\pi r^2}$

At r = 0, it becomes not defined.

It means that r can be any value that is greater than 0. Hence, the correct option is (c). i.e. {r|r>0}

3 0

4 years ago

Find some means. Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random vari

mr_godi [17]

COMPLETE QUESTION:

Find some means. Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50 and standard deviation 8. Find the mean of the random variable Z for each of the following cases. Be sure to show your work.

a) Z = 35-10X

b) Z = 12X-5

c) Z = X+Y

d) Z = X-Y

e) Z = 2X+2Y

Answer:

a) -265

b) 355

c) 80

d) -20

e) 40

Step-by-step explanation:

The attachment below contains the whole calculations that provides for the answers above

6 0

3 years ago

Solve the following equations below by showing all the steps.<br> - 1. 9(4 - 2x) – 3 = 4 - 6(3x – 5)

In-s [12.5K]

Answer:

No real solution

Step-by-step explanation:

First off I'm assuming that the 1 or -1 at the begging is just the problem number:

First you distribute on both sides

36 - 18x - 3 = 4 - 18x + 30

Then combine like terms

33 - 18x = 34 - 18x

Then rearrange the terms by adding 18x to both sides and subtracting both sides by 33. You should get:

0 = 1

When you add positive 18x it cancels the -18x out. And 34 - 33 is 1. Obviously, zero cannot equal 1 so there is no real solution

6 0

4 years ago

Which situation can be represented by the equation -4× 5= -20?​

Which situation can be represented by the equation -4× 5= -20?