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alexandr402 [8]
3 years ago
12

The surface area, S, of a sphere of radius r feet is S = S(r) = 4πr2. Find the instantaneous rate of change of the surface area

with respect to the radius r at r = 4.
a. 32pi
b. 16pi
c. 64pi
d. 4pi
Mathematics
1 answer:
Ksju [112]3 years ago
8 0
S = 4πr^2
Instantaneous rate of change = dS/dr = 8πr
At r = 4, Instantaneous rate of change = 8π(4) = 32π.
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Answer:

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Step-by-step explanation:

Given the expression

2ab^2-\frac{a^2b^2}{5}

\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}

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\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

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Thus,

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