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lesya [120]
1 year ago
10

Determine the measure of the indicated angle in the following triangle:

Mathematics
1 answer:
devlian [24]1 year ago
3 0

Answer:

Θ ≈ 58°

Step-by-step explanation:

using the Cosine Rule in the triangle

cosΘ = \frac{80^2+60^2-70^2}{2(80)(60)} = \frac{64000+3600-4900}{9600} = \frac{5100}{9600} = \frac{51}{96} , then

Θ = cos^{-1} ( \frac{51}{96} ) ≈ 58° ( to the nearest degree )

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andrew-mc [135]
\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

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Write the divide fraction horizontally:
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= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

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Factorise the numerators and denominators when possible:
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= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

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Convert the divide fraction to multiplication fraction
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= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

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Cancel the factors
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Combine to single fraction
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