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Lemur [1.5K]
3 years ago
12

SImplify and divide the following radical expression: √2/√6

Mathematics
2 answers:
Ivenika [448]3 years ago
7 0

Answer:

2 markety mark 3

Step-by-step explanation:

kap26 [50]3 years ago
5 0

Answer:   so the square root od 2 is 1 and 2

and the square root of 6 is 2 and 3

and idk the simplist for for it srry

Step-by-step explanation:

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Step-by-step explanation:

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Use Theorem 2.1.1 to verify the logical equivalence. Give a reason for each step. -(pv –q) v(-p^q) = ~p
sertanlavr [38]

Answer:

The statement \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) is equivalent to \lnot p, \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p

Step-by-step explanation:

We need to prove that the following statement \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) is equivalent to \lnot p with the use of Theorem 2.1.1.

So

\lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv

\equiv (\lnot p \land \lnot(\lnot q))\lor(\lnot p \land \lnot q) by De Morgan's law.

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\equiv \lnot p \land t by the Negation law

\equiv \lnot p by Universal bound law

Therefore \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p

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