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3 years ago

I need help on this question

Mathematics

1 answer:

stepladder [879]3 years ago

5 0

Clockwise 90 is the same as counterclockwise 270. Since 270+90=360, going 270 degrees one way is the same as going 90 degrees the other way.

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1.Solve the equation 2x^2+10x=0 . Check your solution(s) and state the final solution set.

Setler [38]

2x^2 + 10x = 0

we can take out x from both terms and we get:
x(2x + 10) = 0

now either x has to be equal to 0 or 2x + 10 has to be equal to zero in order for equation to be equal to 0.

one solution is x=0 as stated above

other is:
2x + 10 = 0
2x = -10
x = -10/2 = -5

Answers are x=0 and x = -5.

3 0

3 years ago

Susan reads a book at a rate of 1 page every 3 minutes. If her reading rate remains the same, which method could be used to dete

Black_prince [1.1K]

Multiply 18 by 3

hope this helps

6 0

3 years ago

Read 2 more answers

Matthew helped clean the kitchen for 1/3 hour. He helped with the laundry for 1| 1/2 hours.

klio [65]

Answer:

1 | 5/6 hours is the correct answer

Step-by-step explanation:

1 1/2 + 1/3

1 3/6 + 2/6

1 5/6

6 0

3 years ago

Determine the range for the function y = (x - 3 )^2 + 4.

Aleksandr [31]

Answer:

<h3>Solutions are x=2 and x=−2 . At these points the function has vertical asymptotes. To address the range, let's first transform...</h3>

7 0

3 years ago

#10 i The table shows the admission costs (in dollars) and the average number of daily visitors at an amusement park each the pa

lions [1.4K]

The line of best fit is a straight line that can be used to predict the

average daily attendance for a given admission cost.

Correct responses:

The equation of best fit is; $\underline{ \hat Y = 1,042 - 4.9 \cdot X_i}$

The correlation coefficient is; r ≈<u> -0.969</u>

<h3>Methods by which the line of best fit is found</h3>

The given data is presented in the following tabular format;

$\begin{tabular}{|c|c|c|c|c|c|c|c|c|}Cost, (dollars), x&20&21&22&24&25&27&28&30\\Daily attendance, y&940&935&940&925&920&905&910&890\end{array}\right]$

The equation of the line of best fit is given by the regression line

equation as follows;

$\hat Y = \mathbf{b_0 + b_1 \cdot X_i}$

Where;

$\hat Y$ = Predicted value of the<em> i</em>th observation

b₀ = Estimated regression equation intercept

b₁ = The estimate of the slope regression equation

$X_i$ = The <em>i</em>th observed value

$b_1 = \mathbf{\dfrac{\sum (X - \overline X) \cdot (Y - \overline Y) }{\sum \left(X - \overline X \right)^2}}$

$\overline X$ = 24.625

$\overline Y$ = 960.625

$\mathbf{\sum(X - \overline X) \cdot (Y - \overline Y)} = -433.125$

$\mathbf{\sum(X - \overline X)^2} = 87.875$

Therefore;

$b_1 = \mathbf{\dfrac{-433.125}{87.875}} \approx -4.9289$

Therefore;

The slope given to the nearest tenth is b₁ ≈ -4.9

$b_0 = \mathbf{\dfrac{\left(\sum Y \right) \cdot \left(\sum X^2 \right) - \left(\sum X \right) \cdot \left(\sum X \cdot Y\right)} {n \cdot \left(\sum X^2\right) - \left(\sum X \right)^2}}$

By using MS Excel, we have;

n = 8

∑X = 197

∑Y = 7365

∑X² = 4939

∑Y² = 6782675

∑X·Y = 180930

(∑X)² = 38809

Therefore;

$b_0 = \dfrac{7365 \times 4939-197 \times 180930}{8 \times 4939 - 38809} \approx \mathbf{1041.9986}$

The y-intercept given to the nearest tenth is b₀ ≈ 1,042

The equation of the line of best fit is therefore;

$\underline{\hat Y = 1042 - 4.9 \cdot X_i}$

The correlation coefficient is given by the formula;

$\displaystyle r = \mathbf{\dfrac{\sum \left(X_i - \overline X) \cdot \left(Y - \overline Y \right)}{ \sqrt{\sum \left(X_i - \overline X \right)^2 \cdot \sum \left(Y_i - \overline Y \right)^2} }}$