All categories

3 years ago

I need help on this question

Mathematics

1 answer:

stepladder [879]3 years ago

5 0

Clockwise 90 is the same as counterclockwise 270. Since 270+90=360, going 270 degrees one way is the same as going 90 degrees the other way.

You might be interested in

Help plweaseeeee thanks

Sedaia [141]

Answer:

first triangle (to left) b=8, second one c=17

Step-by-step explanation:

for the first triangle (one to the left) the hypotenuse is 9, so let's use the pythagorean formula.

A^2 + B^2 = C^2

^ ^ ^

^ ^ Hypotenuse

^ second side

first side

Substitute:

5^2 + b^2 = 9^2

SImplify:

25+b^2 = 81

Reduce:

b^2 = 64

Simplify:

b=8

In the second triangle, we are given 2 sides.

Let's do the same thing we did in the first one.

Givens:

A = 8

B = 15

Find:

Substitute:

8^2 + 15^2 = c^2

Simplify

64 + 225 = c^2

Reduce:

289 = c^2

Let's now square root both sides

square root of 289 is 17

so we are left with this:

c=17

Phew, you did it!

Hope this helped :))

4 0

3 years ago

Solve for y<br> 3x+1/5y=7

Tcecarenko [31]

Answer:

y = -15x + 35

Step-by-step explanation:

3x + 1/5y = 7

1/5y = -3x + 7

y = 5( -3x + 7)

y = -15x + 35

6 0

3 years ago

A healthy human heart beats about 1,533,000 times a year. A sparrow's heart beats about 241,776,000 times in a year. About how m

Galina-37 [17]

Answer:

About 158 times

Step-by-step explanation:

Represent the rate of human heart with H and sparrow's heart with S

$H = 1,533,000\ times$

$S = 241,776,000\ times$

Required

Determine how many times faster is S than H

To do this, we simply divide S by H i.e.

$Number = \frac{S}{H}$

$Number = \frac{241,776,000}{1,533,000}$

$Number = 157.714285714$

$Number = 158$ --- approximated

<em>Hence, the sparrow's heart beats about 158 times faster than the human hearts</em>

5 0

3 years ago

Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa

Furkat [3]

Given:

Distance between two buildings = $3x^3- x^2 + 7x +100$ feet apart.

Distance between highway and one building = $2x^2 + 7x$ feet.

Distance between highway and second building = $x^3 + 2x^2 - 18$ feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

$W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)$

$W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18$

Combining like terms, we get

$W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)$

$W=2x^3-5x^2+0+118$

$W=2x^3-5x^2+118$

Therefore, the width point highway is $2x^3-5x^2+118$ .

3 0

3 years ago

Electricity travels how many miles per second

Solnce55 [7]

Electricity travels at 186,000 MPS

6 0

3 years ago