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deff fn [24]
3 years ago
9

ok 1 more bois lessststasouhbgiulhgipufgpoeurfbpasiuhgk;jfghusad;fngkfd;jhvga;kl';hsvV/AGVBDNLvbngsflavjb,asd

Mathematics
2 answers:
Nadya [2.5K]3 years ago
5 0

Answer:

woooooo thankssss!! haha

olganol [36]3 years ago
3 0

Answer ok? ;-; thx

Step-by-step explanation:

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*BRAINLIEST* (EASY QA: Warm UP) Find a positive solution to each equation: x2 = 1/4
Georgia [21]

\qquad\qquad\huge\underline{{\sf Answer}}

\textbf{Let's get it solved :}

  • \sf{x² = \dfrac{1}{4}}

  • \sf{x = \sqrt{\dfrac{1}{4}}}

  • \sf{x= \pm{\dfrac{1}{2}}}

  • \sf{x ={\dfrac{1}{2}} }

\textsf{[ since we need positive solution ]}

\textsf{Correct choice is C}

4 0
3 years ago
Read 2 more answers
If 3^4(81^2) = 3^n, what is n?
Mama L [17]

Answer:

n = 16

Step-by-step explanation:

3^4(81^2) = 3^n

3^4(3^4) = 3^n

3^16 = 3^n

n = 16

8 0
4 years ago
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
Name the marked angle two different ways
katrin2010 [14]

tbh I have no Idea ask your mother

3 0
2 years ago
Identify the problem with the following study. A local newspaper published the results of a study that claimed "482 people use t
natita [175]

Answer:

well, only 87 people were asked. How did they get 482?

also, they should have asked the people in the library.

8 0
3 years ago
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