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Nina [5.8K]
3 years ago
9

Find the equation of a line that passes through the point (0, -2) and is parallel to a line that goes through the points (4, 0)

and (0, 3)
Mathematics
1 answer:
Nikitich [7]3 years ago
3 0

Answer:

y = (-3/4)x -2

or: y = -0.75x -2

Step-by-step explanation:

First, find the slope of the line that it parallel to. Using equation

slope m = (y2-y1)/(x2-x1),

slope of line that passes through points (4, 0) and (0, 3)

= (3 - 0) /( 0-4)

= -3/4

Since the lines are parallel, both of them have the same slope, which is -3/4.

The point (0, -2) is actually the point of y -intercept (c) of the new line, so we can simply use the slope-intercept form to find the equation of line.

y = mx + c

y = (-3/4)x + (-2)

y = (-3/4)x -2

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assuming they havve same height

first one is
v=hpi5^2
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2nd one
c=2pir=20pi
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2r=20
r=10
v=hpir^2
v=hpi10^2
v=100hpi

big/small=100hpi/25hpir=4

4 times greater
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2 years ago
1/2x + 5y- 10< 0 The point (4,y) is a solution for the inequality shown. What is the value for y.
finlep [7]
Subtract x on both sides the result you divide it by 5
8 0
3 years ago
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Brett painted three walls. Each wall was 9 ft tall and 12 ft long. How much wall area did he paint
julsineya [31]

Answer:

First we need to calculate the are of each wall, since we alredy knew the length (l) and the width (w) which is the height of the wall in this case:

A = wl = 9 . 12 = 108 (ft²)

We also know that he painted 3 walls, we need to multiply our first result by 3, in other words, the area of wall that Brett painted is the sum of the area of three walls: 108 . 3 = 324 (ft²)

8 0
3 years ago
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Anyone know how to do this
svlad2 [7]

Answer:

The area of the rectangle on the left side is

9cm \:  \times 4cm = 36 {cm}^{2}

The area of the bottom rectangle is

6cm \times 2cm = 12 {cm}^{2}

The total area of the composite figure will be

36 {cm}^{2}  + 12 {cm}^{2}  = 48 {cm}^{2}

Step-by-step explanation:

The area of any given rectangle can be found by multiplying the length of that rectangle by its width. The rectangle on the left side has a length of 9cm but the width is unknown. To find the width, we subtract 6cm from the width of the bottom rectangle: 10cm. And that gives us 4cm.

Therefore, we can now calculate the area to be: length × width = 9cm × 4cm = 36cm²//

The area of the bottom rectangle can be found similarly by multiplying the length: 2cm by the width: 6cm of that rectangle. And the result gives us: 2cm × 6cm = 12cm²//

The total area of the composite figure is calculated by adding the results from the left and bottom rectangles together. And that gives us: 36cm² + 12cm² = 48cm²//

8 0
3 years ago
The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard devia
KengaRu [80]

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

W = \frac{X-\mu}{\sigma} = \frac{X-70}{4}

The values of the cumulative distribution function of W, denoted by \phi , can be found in the attached file. Lets call y = \frac{z-70}{4} . We have

0.1 = P(X > z) = P(\frac{X-70}{4} > \frac{z-70}{4}) = P(W > y) = 1-\phi(y)

Thus

\phi(y) = 1-0.1 = 0.9

by looking at the table, we find that y = 1.28, therefore

\frac{z-70}{4} = 1.28\\z = 1.28*4+70 = 75.12

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .

Download pdf
8 0
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