All categories

3 years ago

Determine the constant of proportionality in each of the representations below.

Mathematics

2 answers:

cluponka [151]3 years ago

7 0

Answer:

Pretty sure is 15

Step-by-step explanation:

90 divided by 6 is 15.

katen-ka-za [31]3 years ago

3 0

Answer:

The constant of proportionality, k is 15

Step-by-step explanation:

The constant of proportionality is the ratio between two directly proportional quantities.

Proportional quantities can be described by the equation y = kx, where k is a constant ratio.

Here, "x" is the number of tickets and "y" is the number of dollars.

k = 30/2 = 15/1 or 15

k = 15

k = 60/ 4 = 30/2 = 15/1 or 15

k = 15

k = 90/6 = 30/2 = 15/1 0r 15

k = 15

When we take the ratio of x and y for all the given values, we get an equal value for all the ratios.

Therefore, the constant of proportionality, k is 15

You might be interested in

I dont get this can someone please help me.

lora16 [44]

$5+\dfrac x 2 \geq 10\\\\\implies \dfrac x2 \geq 10-5\\\\\implies \dfrac x2 \geq 5\\\\\implies x \geq 5 \times 2\\\\\implies x \geq 10$

6 0

2 years ago

Read 2 more answers

Factor completely 3x2-36x+96

allsm [11]

Answer:

do the possible math functions first like 3 x 2 and 6 + 96

3 0

2 years ago

The median income for a sample of people from Chicago is about $60,000 and the

Serhud [2]

Answer:

106,000 is the answer help me with my answer to

5 0

3 years ago

Read 2 more answers

A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the

Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

25% of all adults had used the Internet for such a purpose

This means that $\pi = 0.25$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What is the required sample size for the new study?

This is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}$

$\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2$

$n = 800.3$

Rounding up:

The required sample size for the new study is 801.

4 0

2 years ago

The two dot plots represent a sample of the number of

zheka24 [161]

The answer is:

Both have the same number of data points

Both means are between 3 and 4

Westwood has less variability than Middleton

8 0

2 years ago

Read 2 more answers